Answer:
The options showing the different given statements were not provided in this question; however, an orthopaedic nurse receives specialized education and training to care for patients with diseases and disorders of the musculoskeletal system. Therefore, an orthopedic staff nurse is required to have a knowledge of the following:
1. Orthopedic cases and surgical treatments for each.
2. Surgical site care and dressing.
3. Pain management.
4. Intravenous and Intramuscular drug administration.
5. Vital signs check and significant changes.
6. Post-op care of patient.
7. Casting
8. External fixation care
9. Neurovascular status monitoring
10. Traction
Answer:
If there is homologous chromosomes (metaphase I) or duplicated chromosomes/sister chromatids (metaphase II) in the middle of the cell.
Explanation:
Meiosis involves two series of nuclear divisions grouped into meiosis I and meiosis II. Each division has the same number of stages i.e prophase, metaphase, anaphase, telophase etc. Meiosis I involves the separation of homologous chromosomes i.e similar but non-identical chromosomes from each parent.
On the other hand, meiosis II involves the separation of sister chromatids (duplicated chromosome). Since METAPHASE is generally characterized by the alignment of chromosome at the middle of the cell for separation in the anaphase stage, it means that the difference between metaphase in meiosis I and II will be whether it is homologous chromosomes that are in the middle or sister chromatids.
Therefore, according to this question, I would know if the cartoon is in metaphase I or II if:
- there are homologous chromosomes in the middle of the cell (metaphase I)
- there are sister chromatids in the middle of the cell (metaphase II).
Answer:
a. Let us consider that L is responsible for late and l is responsible for early. From the mentioned data, it can be concluded that allele L or late is dominant over early. By crossing plants 1 and 4 we get the expected ratio of 3: 1, which shows that it follows Mendel's law of dominant.
b. The genotype of all the four plants are:
1st plant = Ll
2nd plant = ll
3rd plant = LL
4th plant = Ll
c. If the plant 1 is self-fertilized then the expected progeny will be 3 (late): 1 (early).
In case if the 2nd plant is self-fertilized, the expected progeny will be only early.
In case if the 3rd plant is self-fertilized, the expected progeny will be only late.
In case if the 4th plant is self-fertilized, the expected progeny will be 3 (late): 1 (early).
Answer:
translation rate
Explanation:
Translation rate would be the thing measured in this scenario.
Answer:
The particularly severe winter of 1777-1778 proved to be a great trial for the American army, and of the 11,000 soldiers stationed at Valley Forge, hundreds died from disease. However, the suffering troops were held together by loyalty to the Patriot cause and to General Washington, who stayed with his men.
