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Scorpion4ik [409]
2 years ago
9

Awnser pls i will give brainly

Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
5 0

Answer:

-3 for x, y for -18,  

f  axis to y axis

C

Step-by-step explanation:

You might be interested in
-4x - 28y=56 4x + 14y=-28
ddd [48]
Adding the 2 equations will eliminate x because -4x + 4x = 0
so we get
-14y = 28
y = -2
plug this into the second euqtion:-
4x + 14(-2) = -28
4x  - 28 = -28 
x = 0

answer is x = 0 , y = -2
4 0
3 years ago
What is the area of the rhombus shown below? AC=17 BD=15 AB=11.2 Answers: A. 255 square units B. 190.4 square units C. 16 square
Lena [83]

Answer:

D. 127.5 square units

Step-by-step explanation:

AC=17

BD=15

AB=11.5

Diagonal (1&2) are given, base of the rhombus is also given.

Height is not given

Area of a rhombus given the diagonals

=1/2×d1×d2

Where,

d1=AC=17

d2=BD=15

Area of a rhombus=1/2×d1×d2

=1/2×17*15

=1/2×255

=127.5

D. 127.5 square units

4 0
3 years ago
N(x)=2x+7;(x)=17, what is the value of x so that the function has a given value
miskamm [114]
2(17)+7

34+7

N(17)=41

Brainliest?
5 0
3 years ago
Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we
lord [1]

Answer:

b. 8,800,000.

Step-by-step explanation:

In maria study the number of cars on the road increases by 10% each year.

Total number of cars in the first year =80 million cars.

We will add 10% of 80 million to 80 milion to enable us get the number of cars for the second year.

For year 2 we have;

10% of 80,000,000+80,000,000

\frac{10}{100}*80,000,000+80,000,000

8,000,000 + 80,000,000

88,000,000

number of cars in year 2 = 88 million

We will add 10% of 88 million to 88 milion to enable us get the number of cars for the third year.

\frac{10}{100}*88,000,000+88,000,000

8,800,000+88,000,000

96,800,000

the number of cars on the road in year 3 compared to year 2 will just be the increase which is in BOLD. That is 8,800,000

<em>or simply subtract the number of cars in year 2 from that in year 3;</em>

96,800,000-88,000,000 = 8,800,000

8 0
3 years ago
Read 2 more answers
A polynomial function with a leading coefficient of 1 and multiplicity 1 for each root has these zeros:
Gala2k [10]

Answer:

1.

x - 2 \sqrt{11}

2.

x + 2 \sqrt{11}

5.

x - 4

Step-by-step explanation:

It is correct on Edge!

Give thanks please!

6 0
2 years ago
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