Answer:
When the line intercepts the x axis, this means that y will be 0.
therefore the 2 coordinates the line passes through are (2,-5) and (4,0)
given equation of line:
y=mx+b
where m = slope
b = y-intercept.
Let (2,-5) and (4,0) be (x1,y1) and (x2,y2) correspondingly.
slope of line = y1-y2 / x1 - x2
Now substitute x = 4, y = 0 and m = 5/2 into equation of line to find b.
therefore equation of line will be:
Answer:
The perimeter of square EFGH is 28.28 units
Step-by-step explanation:
Given in the figure as :
EFGH is a square with points E,F,G,H
∵ The measure of each points from center o is same
I.e OE = OF = OG = OH = 5 units
Now, From any of two length from center o , we can measure the length of each side .
So, (OG)² + (OF)² = (GF)²
Or, (5)² + (5)² = (GF)²
Or, 25 + 25 = (GF)²
Or, (GF)² = 50
∴ GF = 5 unit
Similarly each side EF, GH , EH have same length
Now, As The perimeter of square = 4 × side
So, The perimeter of square = 4 × ( 5 )
Or, The perimeter of square = 20 × ( ) = 28.28 unit
Hence The perimeter of square EFGH is 28.28 units Answer
Answer:
Stabilizer with area = 14 cm².
Step-by-step explanation:
Area of the wing = 101.25 cm²
Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.
1/6 of the area of wing =
1/8 of the area of wing =
This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²
Therefore, area of a good stabilizer design from the given options would be 14 cm²