Please help fast. 50 points.
2 answers:
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Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So, is 37°. We can see from the diagram that
would be
143°.
Also, the new bearing is N 25°E. So, would be 25°.
Now we can find . As the sum of the internal angle of a triangle is 180°.
Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is
We can apply the sine rule now.
So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
$45.22
Step-by-step explanation:
The number of miles per gallon can be represented by the ratio:
Since we know the unit rate of 26 miles per gallon of gas, we can set up a proportion, or equivalent ratios, to find the number of gallons needed for 420 miles:
, where 'x' is the number of gallons of gas
cross-multiply and divide: 26x = 420 or x ≈ 16.15 gallons
If gas is $2.80 per gallon, take the total number of gallons needed and multiply by $2.80:
16.15 x $2.80 = $45.22