I'm guessing the sum is supposed to be

Split the summand into partial fractions:


If
, then

If
, then

This means

Consider the
th partial sum of the series:

The sum telescopes so that

and as
, the second term vanishes and leaves us with

Answer:
5z
Step-by-step explanation:
because I leaned it at school
He can make 32 sandwiches. Since he uses 1/8 pound of cheese for each sandwich, he can make 8 sandwiches using 1 pound of cheese (1/8 x 8 = 1). Now that you know he can make 8 sandwiches with 1 pound of cheese, multiply 8 (this is the sandwiches) by 4 (pounds of cheese).