5x−y=4
Solve for y
.
Tap for more steps...
y=−4+5x
Rewrite in slope-intercept form.
Tap for more steps...
y=5x−4
Use the slope-intercept form to find the slope and y-intercept.
Tap for more steps...
Slope: 5
y-intercept: (0,−4)
Any line can be graphed using two points. Select two x
values, and plug them into the equation to find the corresponding y
values.
Tap for more steps...
xy0−4450
Graph the line using the slope and the y-intercept, or the points.
Slope: 5
y-intercept: (0,−4)
xy0−4450
I=ptr
i=(3000)(1461)(3.5%)
i=153405
his cost will be $153 405 by 4 years
It is equivalent too 5.3 and 5.30
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Answer
Given
Sean's house is currently worth $188,900.
According to a realtor, house prices in Sean's neighborhood will increase by 4.8% every year.
To prove
Formula

Where r is the rate in the decimal form.
As given


= 0.048
Put in the formula


Now also calculated monthly.
Formula

As given


= 0.048
Put in the formula



As the approximation quarterly growth rate of the value of sean's house is near the Compounded quarterly interest .
Thus Option (A) is correct.
i.e
The expression
reveals the approximate quarterly growth rate of the value of Sean's house.