M<1=145 and m<2=72 find m

2x+2y=8 in function form step by step please?

nasty-shy [4]

You could get two different functions out of this:

2x + 2y = 8

1). 'y' as a function of 'x'

Subtract 2x from each side: 2y = -2x + 8

Divide each side by 2 :  y = -x + 4

2).  'x' as a function of 'y' :

Subtract 2y from each side: 2x = -2y + 8

Divide each side by 2 :  x = -y + 4

Those two functions look the same, but that's just because the original
equation given in the problem was so symmetrical. In general, they're
not the same function.

7 0

2 years ago

Read 2 more answers

A line intersects the point (6,9) and (7,4). What is the slope intercept equation for this line?

BartSMP [9]

Answer:

im kind of rusty on this math but i think the equation would be y=-5x+b i forgot how to find b tho :( im sorry

6 0

3 years ago

A cylinder with a radius of 12cm and a height of 20cm has the same volume as a cone with a radius of 8cm. What is the height of

ivanzaharov [21]

Answer: 135cm

Step-by-step explanation

Volume of a cylinder = πr²h

Volume of a cone. = 1/3πr²h

The two shapes are both solid shapes.

Since the have same volume, we can then equate the two together and solve for the height of the cone.

Now make H the height and R the radius of the cylinder and h the height and r the radius of the cylinder.

Now equating the two

πR²H = 1/3πr²h

Now substitute for the values now

Multiply through by 3

3πR²H = πr²h

But π is common so it could be obliterated from the equation

3R²H = r²h

3 x 12² x 20 = 8² x h

3 x 144 x 20 = 64 x h

60 x 144 = 64h

8640. = 64h

Therefore

h = 8640/64

= 135cm

8 0

3 years ago

Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

Leya [2.2K]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6$

6 0

3 years ago

6840 customers in 45 days

Leona [35]

The answer to the question

3 0

2 years ago