Hello and Good Morning/Afternoon:
<u>Let's take this problem step-by-step</u>:
<u>What does the information want:</u>
<u>Let's gather some information</u>:
- ΔA'BC' and ΔABC are similar triangles
⇒ Angle B is shared by both triangles
⇒ Angle A' and A are the same, as they are both on parallel
lines, A'C' and AC, and both angles are formed with the
same line AB
⇒ by the <em>Angle-Angle Theorem*</em>, they are similar triangles
<u>If they are similar triangles</u>:
⇒ their side lengths are proportional to each other
⇒ let's set up a proportion

⇒ let's set up a proportion

<u>Answer:</u>
- <u>x= 17.143</u>
- <u>y = 26.25</u>
Hope that helps!
#LearnwithBrainly
Answer:
B because as you move from left to right the pattern increases by 1
Check the picture below.
so is really just a thick trapezoid, or namely a trapezoidal prism 5 inches thick.
so if we just get the area of the trapezoidal face and multiply by the thickness, we'd get it's volume
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{parallel~sides}{bases}\\ h=height\\[-0.5em] \hrulefill\\ a = 8\\ b = 13\\ h = 6 \end{cases}\implies A=\cfrac{6(8+13)}{2}\implies A=63 \\\\\\ \stackrel{\textit{area of the trapezoidal prism}}{63\cdot 5\implies \stackrel{in^3}{315}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%20%3D%208%5C%5C%20b%20%3D%2013%5C%5C%20h%20%3D%206%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B6%288%2B13%29%7D%7B2%7D%5Cimplies%20A%3D63%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20trapezoidal%20prism%7D%7D%7B63%5Ccdot%205%5Cimplies%20%5Cstackrel%7Bin%5E3%7D%7B315%7D%7D)
Answer:
None
Step-by-step explanation:
Woodchucks can't chuck wood