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2 years ago

Help...........................................................................................

Mathematics

1 answer:

Gala2k [10]2 years ago

8 0

Answer:

How much the tree grew a week

Step-by-step explanation:

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When 58,511 is divided by 21, the quotient is 2,786 R ___. Numerical Answers Expected!

Marta_Voda [28]

The answer is 2,786 R5

3 0

2 years ago

What is the 10th term in the increasing pattern shown? 1, 1, 2, 3, 5, 8, 13

Vika [28.1K]

Answer:

Step-by-step explanation:

(after the first "1") You need to add the previous two numbers together to get the next number in the pattern.

7 0

2 years ago

Find the lateral area of the cone in terms of π.

Andreyy89

Answer:

$15\pi\ cm^{2}$

Step-by-step explanation:

we know that

The lateral area of the cone is equal to

$LA=\pi rl$

where

r is the radius of the base

l is the slant height

we have

$r=3\ cm$

Applying the Pythagoras Theorem find the slant height

$l^{2}=3^{2} +4^{2}\\ \\l^{2}=25\\ \\l=5\ cm$

substitute in the formula

$LA=\pi (3)(5)=15\pi\ cm^{2}$

8 0

2 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

2 years ago

Talia spent 3/4 of this week's allowance on candy. Of the money she spent on candy, 5/6 was spent on gummy bears. What fraction

Anna71 [15]

Tabia spent 15/24 of this week's allowance on gummy bears. She can calculate that by multiplying 3/4 times 5/6. To do that, she multiplies the top numbers of each fraction together (3 times 5 equals 15), and to get the top number of the fraction. Then she multiplies the bottom numbers together (4 times 6 equals 24) to get the bottom number.

3 0

2 years ago