22. 30 degrees because line DB bisects(meaning cuts in half) angle ABC so DBC should be 30 degrees because 30+30 is 60 which is what angle ABC is.
23. 60 degrees because if we assume that it is a parallelogramand that the opposite angle are congruent.
24. 120 degrees because a quadrilatteral has sides that will equal to 360 degrees, and I said that a parallelogram will have its opposite angles congruent we take away 120 from 360 (from the previous angles ABC and BCD) we end up with 240, we divide 240 by 2 and end up with 120 degrees
25. 60 degrees. I found that angle DCB is 120 degrees so angles DCB and DCE are supplementary(add up to 180 degrees) and we subtract 120 from 180 which is 60 degrees.
26. 60 degrees vertical to angle DCE.
27. 120 degrees supplementary to DCE
Answer:
angle HMS = 62 degrees
x = 13 degrees
AT = 28
Step-by-step explanation:
angle SHM and angle HMS are both inside the triangle SMH.
We want to find the angle of HMS. We know that the sum of the angles in the triangle adds up to 180 degrees. There are two angles that we already know.
Angle SHM = 28 (given)
Angle HSM = 90 (because it is a right angle which is always 90 degrees, right angles are formed at two perpendicular lines)
Angle HMS = x (we let angle HMS be a variable as we don't know the value for it)
x + 90 + 28 = 180
x = 62 ddegrees
HMS is 62 degrees
TSA is a right angle in triangle AST because it is formed by two perpendicular lines. Right angles always equal 90 degrees.
10x - 40 = 90
10x = 130
x = 13 degrees
AT and HT are both congruent sides. We know this because the figure we are given is a kite. In a kite, we have two pairs of sides that are congruent to each other. HT is congruent to AT while HM is congruent to AM.
So,
8x - 4 = 2x + 20
Subtraact 2 x from both sides
6x - 4 = 20
Add 4 to both sides
6x = 24
Divide 6 on both sides.
x = 4
Plug x back to AT.
AT = 2(4) + 20 = 28
Answer:
10x^8 is the sum
Step-by-step explanation: