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mixer [17]
3 years ago
10

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Mathematics
1 answer:
borishaifa [10]3 years ago
8 0

Answer:

is it 7?

Step-by-step explanation:

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In a doctor's waiting room, there are 14 seats in a row. Eight people are waiting to be seated. There is someone with a very bad
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¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆  x 3! 

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Another way to solve this problem is as follow:

5 + (3) people are considered (for the time being) as 6 entities:

The 1st has a choice among 14 ways

The 2nd has a choice among 13 ways

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But the 3 (that formed one group) could seat among themselves in 3!

or 6 ways:

Total number of permutation = 2,162,160 x 6 = 12,972,960

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Answer:

Your answer is correct.

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