Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

. The two bottles are similar in shape. The larger bottle holds 100 m/ of perfume. Calculate how many millilitres of perfume the

FromTheMoon [43]

Answer:

The smaller bottle holds 12.5 ml of perfume.

====================

<h2>Given</h2>

Two bottles of similar shape;
Larger bottle has volume of 100 ml;
The length of larger bottle is 10 cm;
The length of smaller bottle is 5 cm.

The volume of smaller bottle.

<h2>Solution</h2>

Find the scale factor, the ratio of corresponding dimensions:

$k = 5/10 = 1/2$

We know the volume is the function of three dimensions, therefore the ratio of volumes is the cube of the scale factor:

$V_{small}/V_{large} = k^3\\$

Substitute the known values and find the volume of small bottle:

$V_{small}/100= (1/2)^3\\$
$V_{small}/100= 1/8$
$V_{small}= 1/8*100=12.5$

The smaller bottle holds 12.5 ml of perfume.

4 0

2 years ago

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The equation below represents the trend line of a scatter plot showing the hours spent studying versus science test scores.

navik [9.2K]

Answer:

On the science test the point ( 0 , 424 ) the intercepts is bigger

Step-by-step explanation:

The relation hours spend vs science test score is

y = 6.5*x + 424

And the relation hours spend vs Maths test score is

y = 7.2*x + 34.7

Making x = 0 ( student does not study at all ) we get:

For science score test woul be

y = 0 + 424

In case of maths

y = 0 + 34.7

That mean student without studying will get better score in science.

The point ( 0 , 424) ( science ) represents the interception with y axis

in Maths case such point is ( 0 . 34.7)

7 0

3 years ago

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Please help!!!!!!!!!!!

AVprozaik [17]

I can’t view the photo.

7 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

Simplify -3p3 + 5p + (-2p 2) + (-4) - 12p + 5 - (-8p3). Select the answer in descending powers of p.

BigorU [14]

-3p^3 + 5p -2p^2 - 4 - 12p + 5 + 8p^3
5p^3 - 2p^2 - 7p + 1

It is the second choice

7 0

3 years ago