Answer:
f(x)=0.333*(1*x+-4)*(1*x+1)
Step-by-step explanation:
<u>Your exercise:</u>
Find a quadratic function with roots at 4 and -1 whose graph goes through the point -2 .
The function f(x)=a*(1*x+-4)*(1*x+1) has the desired roots.
Insert the point (1, -2) to find a.
-2=a*(1*1+-4)*(1*1+1)
-2=1*a*(1*1+-4)*(1*1+1) (add 1 to -4)
-2=1*a*-3*(1*1+1) (add 1 to 1)
-2=1*a*-3*2 (Multiply -3 by 2)
-2=1*-6*a (Swap both sides of the equation.)
-6*a=-2 : (-6)
1*a=0.333
f(x)=0.333*(1*x+-4)*(1*x+1)
Answer:
C. √2 - 1
Step-by-step explanation:
If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)
Let r = the radius of the small circle
Using Pythagoras' Theorem
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
to find the diagonal of the square:
So the diagonal of the square =
We are told that the radius of the large circle is 1:
⇒ Diagonal of square + r = 1
Using the quadratic formula to calculate r:
As distance is positive, only
Answer:
45 or least
Step-by-step explanation:
I'm guessing that the angel is acute
Answer:
[f(1) - f(3)] / [1–3]
Step-by-step explanation:
<u>Formula</u>
f(x) = 6(2.5)
<u>How to find</u>
The average rate of change over the interval [a,b], or the secant line between the points a and b on the function f(x), is [f(a) - f(b)]/[a-b]. So, substitute a for 1 and b for 3, and you get [f(1) - f(3)] / [1–3]. The quotient of that is your average rate of change.