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2 years ago

8

Mr. Prescott cuts 1/3 of a piece of construction paper. He uses 1/6 of the piece to make a flower. What fraction of the sheet of

paper does he use to make the flower?

1 answer:

algol [13]2 years ago

8 0

1/3 • 1/6
1/18 is the fraction

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Please help me with 4 more questions ill give brainliest plesase!!

slavikrds [6]

Answer:

(- 1, - 1 )

Step-by-step explanation:

Since the dilatation is centred at the origin, then multiply the coordinates of the original point by the scale factor, that is

(- 3, - 3 ) → ( $\frac{1}{3}$ × - 3, $\frac{1}{3}$ × - 3 ) → (- 1, - 1 )

6 0

2 years ago

What is 7 divided by 44

ipn [44]

Answer:

0.1590909999999001

Step-by-step explanation:

5(*$85$84#58$58$85$&(xgkzgkzgkz&)$"(*85dtkdtistozogzfizfjzfjzfjsotyd

3 0

2 years ago

In Exercises 3–10, use the Chain Rule to calculate the partial derivatives. Express the answer in terms of the independent varia

sashaice [31]

I'll use subscript notation for brevity, i.e.

$\dfrac{\partial f}{\partial x}=f_x$

3.

$f(x,y,z)=xy+z^2\implies\begin{cases}f_x=y\\f_y=x\\f_z=2z\end{cases}$

$x(r,s)=s^2\implies\begin{cases}x_r=0\\x_s=2s\end{cases}$

$y(r,s)=2rs\implies\begin{cases}y_r=2s\\y_s=2r\end{cases}$

$z(r,s)=r^2\implies\begin{cases}z_r=2r\\z_s=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=2xs+4zr=2s^3+4r^3$

$f_s=f_xx_s+f_yy_s+f_zz_s=2ys+2xr=6rs^2$

4.

$x(r,s,t)=r+s-2t\implies\begin{cases}x_r=1\\x_s=1\\x_t=-2\end{cases}$

$y(r,s,t)=3rt\implies\begin{cases}y_r=3t\\y_s=0\\y_t=3r\end{cases}$

$z(r,s,t)=s^2\implies\begin{cases}z_r=0\\z_s=2s\\z_t=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=y+3xt=3rt+3r+3s-6t^2$

$f_s=f_xx_s+f_yy_s+f_zz_s=y+4zs=3rt+4s^3$

$f_t=f_xx_t+f_yy_t+f_zz_t=-2y+3xr=3r+3s-12rt$

8 0

2 years ago

Is x-2 a factor of 4x^5 +5x^4 +1?

nordsb [41]

Answer:

No

Step-by-step explanation:

By the Factor theorem

If (x - h) is a factor of f(x) then f(h) = 0

Here (x - 2) with h = 2 and f(x) = 4 $x^{5}$ + 5 $x^{4}$ + 1 , then

f(2) = 4 $(2)^{5}$ + 5 $(2)^{4}$ + 1

= 4(32) + 5(16) + 1

= 128 + 80 + 1

= 209

Since f(2) ≠ 0 then ( x - 2) is not a factor

8 0

2 years ago

Find the Least Common Multiple (L.C.M) and Highest Common Factor (H.C.F) of 20 and 30.

Archy [21]

Answer:

LCM: 60

HCF: 10

Step-by-step explanation:

Listing Multiples

LCM:

Multiples of 20:

20, 40, 60, 80, 100

Multiples of 30:

30, 60, 90, 120

Therefore,

LCM(20, 30) = 60

----------------------------------------

Factorization

HCF:

The factors of 20 are: 1, 2, 4, 5, 10, 20

The factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30

Then the greatest common factor is 10

8 0

2 years ago