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3 years ago

80,531 rounded to nearest thousand

Mathematics

2 answers:

mario62 [17]3 years ago

5 0

Answer:

81,000

Step-by-step explanation:

Find the number in the thousand place 0 and look one place to the right for the rounding digit 5. Round up if this number is greater than or equal to 5 and round down if it is less than 5. So the answer is 81,000

Vlad [161]3 years ago

4 0

Answer:

81,000

Step-by-step explanation:

go to whatever place it is asking you to round nearest to the if it is 5 or more you round up 4 or less it stays the same.

Saying for this -" 5 or more raise the score, 4 or less let it rest"

^round up^ ^stays the same^

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If m< BOE = 130 degrees and m< cob = 80 degrees

hjlf

Answer:

then what?

Step-by-step explanation:

do we have to find the angle?

all I know is every right triangle is equal to 90°

6 0

3 years ago

Which of these numbers is in the solution set of x + 5 = 15? A. 10 B. 3 C. 20 D. 11

stealth61 [152]

Answer:

Step-by-step explanation:

10 + 5 = 15

6 0

3 years ago

Read 2 more answers

The surface areas of two similar solids are 169 m2 and 81 m2. the volume of the larger solid is 124.92 m3. which proportion corr

ikadub [295]

By finding the scale factor, we will see that the volume of the smaller solid is 86.75 m³.

<h3>How to get the volume of the smaller solid?</h3>

If the solids are similar, then there is a scale factor between the two. Then the relation between the areas is equal to the scale factor squared, and the relation between the volumes is equal to the scale factor cubed.

This means that if the areas are 169 m² and 81 m², then we can write:

169 m² = (k²)*81 m²

Solving for k, we get:

k = √(169 m²/81 m²) = 1.44

Then if the volume of the large solid is 124.92m³ we can write:

124.92m³ = k³*V

Replacing k and solving for V we get:

124.92m³ = (1.44)³*V

(124.92m³/ (1.44)³) = V = 86.75 m³

If you want to learn more about scale factors:

brainly.com/question/3457976

#SPJ4

6 0

2 years ago

Read 2 more answers

A snail can move 1/30 miles in 1/3 hour. How fast does a snail move in miles /hours

bekas [8.4K]

Answer: 1/10 miles/hour

To find how fast a snail moves in miles per hour, we can find the unit rate using a proportion.

The unit rate is the amount per one unit. In this problem, the unit is for one hour. One way to find the unit rate is by using a proportion.

<h2>Proportions</h2>

Proportions look like two fractions set equal to each other with a missing variable to solve.

<h3>State our variables</h3>

let <em>x</em> be the number of miles per hour

<h3>Write a proportion</h3>

The first fraction has a number for the numerator (top) and denominator (bottom), because the question gives us the information. The second fraction has a missing value, <em>x</em>, that we are solving for. We can write <em>x</em> in the numerator.

$\displaystyle{\frac{\frac{1}{30}\ mi}{\frac{1}{3}\ hr} = \frac{x\ mi}{1\ hr}}$

<h2>Solve</h2>

We can solve by finding the scale factor. The scale factor is the number we can multiply the numerator by to find <em>x</em>.

<h3>Find the scale factor</h3>

Start with the proportion.

$\displaystyle{\frac{\frac{1}{30}\ mi}{\frac{1}{3}\ hr} = \frac{x\ mi}{1\ hr}}$

To find the scale factor,

Take the denominator from the fraction with a variable: $1\ hr$
Take the denominator from the fraction that has no variable: $\frac{1}{3}\ hr$
Divide step 1 by step 2 and solve: $1\ hr\ \div\ \frac{1}{3}\ hr = 3$

Our scale factor is <u>3</u>.

<h3>Solve for x</h3>

We can find <em>x</em> by multiplying the numerator in the first fraction by the scale factor. This is because <em>x</em> is also in the numerator.

$\displaystyle{\frac{\frac{1}{30}\ mi}{\frac{1}{3}\ hr} = \frac{(\frac{1}{30}\ mi)*3}{1\ hr}}$

$\displaystyle{\frac{\frac{1}{30}\ mi}{\frac{1}{3}\ hr} = \frac{\frac{3}{30}\ mi}{1\ hr}}$

Simplify 3/30 by dividing the fraction by 3.

$\displaystyle{\frac{\frac{1}{30}\ mi}{\frac{1}{3}\ hr} = \frac{\frac{1}{10}\ mi}{1\ hr}}$

x = 1/10

∴ a snail moves 1/10 miles per hour.

Learn another way to solve proportions here: brainly.com/question/18437927

7 0

2 years ago

etermine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 3 2 x

nata0808 [166]

Answer:

(32/15, -2/5)

Step-by-step explanation:

(1) ³/₂x - 2y = 4

(2) x + ⅓y = 2

(3) 3x - 4y = 8 Multiplied (1) by 2

(4) 3x + y = 6 Multiplied (2) by 3

5y = -2 Subtracted (3) from (4)

(5) y = -⅖ Divided each side by 5

x + ⅓(-⅖) = 2 Substituted (5) into (2)

x - ²/₁₅ = 2

x = 2 + ²/₁₅ Added ²/₁₅ to each side

x = 32/15

The system of equations has only one solution: (32/15, -2/5).

3 0

3 years ago