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DENIUS [597]
3 years ago
6

LITERALLY PLZ HELP I WILL GIVE BRAINLIEST If you had the opportunity to interview an experienced scientist at NASA who has been

involved in numerous space explorations, what would you want to know? Identify at least three specific questions that you would ask this scientist and briefly explain why you would ask these particular questions.
Physics
1 answer:
Crazy boy [7]3 years ago
3 0
1. What food were you craving the most upon return home after eating space food? - I would ask because they don’t get the regular everyday food we have on earth, I know I’d be craving food and it’s very interesting to hear their answers.

2. How did you feel physically after returning to earth? And has it been hard readjusting? - After a long period of time in space, I feel like it’d be very hard to adjust back into the way we live and I’m intrigued to hear about how it felt and what they did in order to adjust.

3. What do you think while on the launchpad about to launch? - I feel like it’d be very scary for me but everyone has a different way of feeling. I’d love to hear about their thoughts during this process.
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What is the correct calculation for voltage if the resistance is 3 ohms and the current is 4 amps?
denis23 [38]

Answer:

iek

Explanation:

5 0
3 years ago
Chris shoots an arrow up into the air. The height of the arrow is given by the function h(t) = - 16t2 + 64t + 23 where t is the
Ghella [55]

Completing the square gives the answer right away.

-16t^2+64t+23=-16(t^2-4t)+23=-16(t^2-4t+4-4)+23=-16((t-2)^2-4)+23

\implies h(t)=-16(t-2)^2+87

which indicates a maximum height of 87 when t=2.

7 0
3 years ago
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The specific heat capacity of ethanol is 2440J/kg °C. How many joules of energy will be required to heat 150g ethanol to 35°C if
m_a_m_a [10]

Answer:

Required energy = 4758 J

Explanation:

Specific heat capacity of a material is the amount of energy required to raise the temperature of one kilogram (kg) of that material through one degree Celsius (°C).    

Given data :

Specific heat capacity = c = 2440 J/kg.°C

Mass = m = 150 g = 0.15 kg

Initial temperature = 22°C

Final temperature = 35°C

Change in Temperature = ΔT = 13°C

Energy = E = ?

Using the following formula and substituting the values, we get:

E = m × c × ΔT

E = 0.15 × 2440 × 13

E = 4758 J

8 0
3 years ago
8 N to the Lefr and 4 N to the right find the net force is this balanced
olga_2 [115]

Answer:

4N to the left. No it is not balanced.

Explanation:

8 -4 = 4 N of force

Balanced would be if they equaled zero, so 8 to the left and 8 to the right

8 0
4 years ago
Could anyone help with number 9?
Alisiya [41]
The answer would be A
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