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DerKrebs [107]
3 years ago
13

Suppose that a star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen bu

t the violet lines are at 444nm and 420nm instead of the usual 434nm and 410nm. From this evidence, you can conclude that the star is:___________
Physics
1 answer:
ladessa [460]3 years ago
6 0

Answer:

It can be concluded that the star is moving away from the observer.

Explanation:

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving  toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

The wavelength at rest for this case is 434 nm and 410 nm (\lambda_{0} = 434nm, \lambda_{0} = 410nm)

Redshift: \lambda_{measured}  >  \lambda_{0}

Blueshift: \lambda_{measured}  <  \lambda_{0}

Since, \lambda_{measured} (444nm) is greater than \lambda_{0} (434 nm) and \lambda_{measured} (420nm) is greater than \lambda_{0} (410 nm), it can be concluded that the star is moving away from the observer

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The reason for this is that the mass of the electron is smaller (about 1000 times smaller) than the mass of the proton. The two particles have same charge (e), so they experience the same force under the same electric field E:
F=eE 
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we said that the force exerted on the two particles, F, is the same, while the mass of the electron is smaller: therefore, from the last formula we see that the acceleration of the electron will be larger than that of the proton.

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2 years ago
What would happen if you tried to use a prism to disperse a beam that contained only green light?​
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It is determined by the nature of the green light. Because lasers create light at almost a single frequency, green laser light would appear as a thin line of pure green. Other sources of "green" light emit light at a variety of frequencies, including yellow and blue, resulting in a strong green band in the center that fades into blue-green and yellow-green at the borders.

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and here’s a graph of the transmission spectra of several standard photographic filters, including green: Attachment #2

Learn more about the color spectrum:

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marta [7]
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The change in internal energy during one complete cycle of a heat engine A. equals the net heat flow into the engine. B. equals
Stels [109]

Answer:

B. equals zero

Explanation:

Given data

one complete cycle = heat flow

solution

we have given that when heat engine complete 1 cycle change in energy = net heat flow

that is always equal to zero

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ΔU = Q + W

we know ΔU is the change internal energy in system and Q is net heat transfer in system and W is  net work done in system

therefore change of internal energy during one cycle

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