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DerKrebs [107]
3 years ago
13

Suppose that a star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen bu

t the violet lines are at 444nm and 420nm instead of the usual 434nm and 410nm. From this evidence, you can conclude that the star is:___________
Physics
1 answer:
ladessa [460]3 years ago
6 0

Answer:

It can be concluded that the star is moving away from the observer.

Explanation:

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving  toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

The wavelength at rest for this case is 434 nm and 410 nm (\lambda_{0} = 434nm, \lambda_{0} = 410nm)

Redshift: \lambda_{measured}  >  \lambda_{0}

Blueshift: \lambda_{measured}  <  \lambda_{0}

Since, \lambda_{measured} (444nm) is greater than \lambda_{0} (434 nm) and \lambda_{measured} (420nm) is greater than \lambda_{0} (410 nm), it can be concluded that the star is moving away from the observer

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Answer:

  • Metals are good conductors of electricity <u>because they have free electrons</u> which help in the transfer of charge from one point to another.

6 0
3 years ago
A truck has a mass of 2,000 kg. The driving force created by the engine is 3,000 Newtons. Calculate the acceleration caused by t
Brrunno [24]

Answer:

1.5 m/s^2

Explanation:

Force = 3000 Newtons

Mass = 2000 kilograms

Force = Mass x Acceleration

This rearranged to:

Acceleration = Force / Mass

Acceleration = 3000 / 2000 = 1.5 m/s^2

8 0
3 years ago
Assuming perfect optics, if the smallest feature you can resolve when observing around 660 nm is of angular size 0.04 arcsec, wh
Dmitriy789 [7]

Answer:

The value is \theta _2 =  0.08 \ arcsec

Explanation:

From the question we are told that

   The first wavelength is  \lambda_1 =  660 \ nm  = 660 *10^{-9 }

   The  first angular size is  \theta_1 =  0.04 \  arcsec

    The second wavelength is  \lambda _2 =  1320 \  nm  =  1320 *10^{-9 } \  m

Generally according to  Rayleigh Criterion we have that

          \theta=  1.22 *  \frac{\lambda }{D}

given every other thing remains constant we have that

         \theta =  k *  \lambda

Here k  represented constant so

         k  =  \frac{\theta }{\lambda}

=>      \frac{\theta_1}{ \lambda_1}  =  \frac{\theta_2}{ \lambda_2}

=>      \frac{\theta_1}{ \theta_2}  =  \frac{\lambda_1}{ \lambda_2}

So

        \frac{ 0.04}{ \theta_2}  =0.5

=>     \theta _2 =  0.08 \ arcsec

3 0
3 years ago
A bug starts at point A, crawls 8.0 cm east, then 5.0 cm south, 3.0 west, and 4.0 cm north to point B.
Sholpan [36]

Answer:

5cm east& 1cm west from A

Explanation:

https://brainly.ph/question/2753392

7 0
3 years ago
If a force does not act parallel to the resulting displacement, what is the effect on the work done by the force? 
m_a_m_a [10]
Then only the component of the force that's parallel to the displacement
is used to calculate the work.  The component of force that's perpendicular
to the displacement  doesn't move through any distance at all, so its contribution
to the total work is zero.
8 0
3 years ago
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