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quester [9]
3 years ago
14

Solve for x x+4/3 = 6

Mathematics
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

x= 4 2/3

Step-by-step explanation:

Subtract 4/3 from 6 to get X! Hope this helped!

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Complete the table of values for y=6-2x<br><br> Also please work out 6-2x=3
Whitepunk [10]

Answer:

Step-by-step explanation:

x=0     y=6-2*0=6

x=1      y=6-2*1=4

x=2      y=6-2*2=2

x=3      y=6-2*3=0

6-2x=3

-6       -6

-2x=-3

2x=3

:2    :2

x=3/2

x=1.5

3 0
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Marie buys 16 bags of potting soil that comes in 5 - 8 pound bags. If Marie's father calls and he needs 13 pounds of potting soi
vesna_86 [32]
One bag of 5 pounds and one bag of 8 pounds
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A bicycle rider increases his speed from 5 m/s to 15 m/s in 10 seconds
valentina_108 [34]
To find the acceleration of the bicycle rider, we are going to use the acceleration formula: a= \frac{v_{f}-v_{i}}{t}
where
a is the acceleration 
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v_{f} is the final speed 
t is the time 

We know from our problem that increases his speed from 5 m/s to 15 m/s in 10 seconds, so his initial speed is 5 m/s and his final speed is 15 m/s; therefore, v_{i}=5, v_{f}=15, andt=10. Lets replace those values in our formula:
a= \frac{v_{f}-v_{i}}{t}
a= \frac{15-5}{10}
a= \frac{10}{10}
a=1

We can conclude that the acceleration of the bicycle rider 1 m/s^2
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3 years ago
PLEASE HELP! I WILL MARK BRAINLIEST!!!
Minchanka [31]

Answer: I'd say a broad audience made up of all kinds of people

It had different parts and concepts that could entertain any age group

5 0
3 years ago
Read 2 more answers
Which expression has a negative value?
7nadin3 [17]

Answer: The answer would be B

Step-by-step explanation:

I had a test like this so I kinda know wut the answer is a few weeks or so ago but u need to multiply -5 • 5 (which would be negative since it has one negative sign) then multiply -5 • -5 (since it has another negative it’s positive) then u just multiply the answers that u got from the times 5 u did -bonus if it’s 1 negatives it’s a negative but if it’s 2 negatives it’s a positive

4 0
3 years ago
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