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mariarad [96]
3 years ago
7

On a given day, the proportion of workers from Company B who purchase a coffee from the company cafeteria is 0.62 and the propor

tion of workers from Company C who purchase a coffee from the company cafeteria is 0.71. A random sample of 40 workers was selected from Company B and another random sample of 40 workers was selected from Company C. The proportion of workers from Company B who purchased coffee was
Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0

Complete question is;

On a given day, the proportion of workers from Company B who purchase a coffee from the company cafeteria is 0.62 and the proportion of workers from Company C who purchase a coffee from the company cafeteria is 0.71. A random sample of 40 workers was selected from Company B and another random sample of 40 workers was selected from Company C. The proportion of workers from Company B who purchased coffee was p^_B = 0.70 and the proportion of workers from Company C who purchased coffee was p^_C = 0.75.

What is the correct unit of measurement for the mean of the sampling distribution p^_B - p^_C?

A) Days

B) Dollars

C) Companies

D) Workers

E) There are no units associated with the mean of the sampling distribution

Answer:

E) There are no units associated with the mean of the sampling distribution

Step-by-step explanation:

We are given;

Population proportion for workers from Company B who purchase a coffee from the company cafeteria as 0.62

Population proportion for workers from Company C who purchase a coffee from the company cafeteria as 0.71

Now, we were told that a random sample of 40 each were selected from both company B & C and the sample proportion were;

p^_B = 0.70 and p^_C = 0.75

Now, this proportions don't have any units as it is based on a ratio of the number of people that purchased coffee to the number of people surveyed.

Thus we can conclude that p^_B - p^_C will not have any units associated with it.

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3 years ago
HELP PLEASE!!
TiliK225 [7]
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