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vesna_86 [32]
2 years ago
15

9-3X WHAT EQUILS TO 0

Mathematics
2 answers:
hram777 [196]2 years ago
6 0

Answer:

x = 3

Step-by-step explanation:

If the equation was 9-3x=0 then x = 3.

9-3x=0

-9      -9

-3x  = -9

/-3     /-3

x    =   3

AlladinOne [14]2 years ago
4 0

Answer: 3

Step-by-step explanation:

3x3=9

9-9=0

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When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
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Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

We have to sum 528 and three times the number, so we have 528+3x

Then, we have to subtract this number from x^2, so we have

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The result is 120, so the equation is

x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24

But we know that x is positive, so we only accept the solution x = 27

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