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2 years ago

What is the mass of an object that has a density of 1.3 g/cm3 and a volume

Mathematics

1 answer:

tangare [24]2 years ago

8 0

Answer:

The mass of the object is 2.6 grams

Step-by-step explanation:

The density of an object is the ratio between its mass and its volume

The equation of the is d = $\frac{m}{V}$ , where

m is the mass

V is the volume

Let us use this equation to solve the question

∵ An object has a density of 1.3 g/cm³

∴ d = 1.3 g/cm³

∵ Its volume is 2 cm³

∴ V = 2 cm³

→ Substitute them in the equation of the denisty above

∵ 1.3 = $\frac{m}{2}$

→ Multiply both sides by 2

∴ 2 × 1.3 = 2 × $\frac{m}{2}$

∴ 2.6 = m

∴ The mass of the object is 2.6 grams

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2x-y=17
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2x-y=17
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x-y=10
x-(-3)=10
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3 years ago

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3 years ago

Read 2 more answers

The base of a prism has n sides. Find the numbers of faces, edges, and

Harman [31]

Answers:

faces = n+2
edges = 3n
vertices = 2n

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Explanation:

Think of a hexagonal room with n = 6 walls, i.e. the floor is a hexagon with n = 6 sides. The floor and ceiling are parallel to each other, and congruent hexagons. That's 2 faces so far. Then we have another 6 faces to account for the walls. This gives 2+6 = 8 faces of a hexagonal prism.

In more general terms, a prism with a base of n sides will have 2 parallel and congruent base faces, and n walls or lateral faces. This gives n+2 total faces.

------------------------

Let's go back to the hexagonal prism. The floor has 6 sides to it, and so does the ceiling. We have 6+6 = 12 edges so far. Then we have another 6 edges where each of the rectangular walls meet up. That gives 12+6 = 18 edges total of this hexagonal prism room.

For any more general case, each base has n sides. That gives 2n sides so far for just the bases. Then add on another n for the lateral edges and we get 3n total edges.

--------------------------

Once again lets revisit the room with the hexagonal floor and ceiling. The floor has 6 vertices and the ceiling has the same vertex count. Therefore, this prism has 6+6 = 12 vertices.

For the general case, each base has n vertices. There are 2 such identical bases giving 2n vertices total.

---------------------------

One way to check the answer:

We could use Euler's Polyhedron Formula which is

F+V-E = 2

where,