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abruzzese [7]
3 years ago
5

What is the mass of an object that has a density of 1.3 g/cm3 and a volume

Mathematics
1 answer:
tangare [24]3 years ago
8 0

Answer:

The mass of the object is 2.6 grams

Step-by-step explanation:

The density of an object is the ratio between its mass and its volume

The equation of the is d = \frac{m}{V} , where

  • m is the mass
  • V is the volume

Let us use this equation to solve the question

∵ An object has a density of 1.3 g/cm³

∴ d = 1.3 g/cm³

∵ Its volume is 2 cm³

∴ V = 2 cm³

→ Substitute them in the equation of the denisty above

∵ 1.3 = \frac{m}{2}

→ Multiply both sides by 2

∴ 2 × 1.3 = 2 × \frac{m}{2}

∴ 2.6 = m

∴ The mass of the object is 2.6 grams

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(examples) n = 2

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Write a quadratic equation given the roots -1/3 and 5, show your work
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\boxed{(x - a)(x - b) = 0}

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

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These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

(x +  \frac{1}{3} )(x -  5) = 0

Here we can convert the expression x+1/3 to this.

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Rewrite the equation.

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Simplify by multiplying both expressions.

3 {x}^{2}  - 15x + x - 5 = 0 \\ 3 {x}^{2}  - 14x  - 5 = 0

<u>Answer</u><u> </u><u>Check</u>

Substitute the given roots in the equation.

3 {(5)}^{2}  - 14(5)  - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0

3( -  \frac{1}{3} )^{2}  - 14( -  \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) +  \frac{14}{3}  - 5 = 0 \\  \frac{1}{3}  +  \frac{14}{3}  -  \frac{15}{3}  = 0 \\  \frac{15}{3}  -  \frac{15}{3}  = 0 \\ 0 = 0

The equation is true for both roots.

<u>Answer</u>

\large \boxed {3 {x}^{2}  - 14x - 5 = 0}

8 0
3 years ago
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