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Charra [1.4K]
3 years ago
13

Rhombus ABCD has a diagonal BD¯¯¯¯¯.

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0
Use gauthmath it can help with any math problem 3EMB3R use this code to get more tickets
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In the diagram below, MNPQ is a parallelogram whose diagonals are perpendicular. Prove: MNPQ is a rhombus.
katen-ka-za [31]

Answer:

Given : MNPQ is a parallelogram whose diagonals are perpendicular.

To prove :  MNPQ is a rhombus.

Proof:

In parallelogram MNPQ,

R is the intersection point of the diagonals MP and NQ( shown in below diagram)

\implies MR\cong RP (Because, the diagonals of parallelogram bisects each other)

\angle MRQ\cong \angle QRP (Right angles )

QR\cong QR  (Reflexive)

Thus, By SAS postulate of congruence,

\triangle MRQ\cong \triangle PRQ

By CPCTC,

MQ\cong QP

Similarly,

We can prove, \triangle MRN\cong \triangle PRN

By CPCTC,

MN\cong NP

But, By the definition of parallelogram,

MN\cong QP and MQ\cong NP

⇒ MN\cong NP\cong PQ\cong MQ

All four side of parallelogram MNQP are congruent.

⇒ Parallelogram MNPQ is a rhombus.

Hence, proved.

4 0
3 years ago
7. An investment account pays 3.9% interest compounded semi-annually. If
Likurg_2 [28]

Answer:

the balance would be 48000

Step-by-step explanation:

First you really dont have to do with the 3.9%

If 4000 is invested and you need the balance after 12 years you just multiply

4000 times 12=48000

5 0
4 years ago
The perimeter of a rectangular garden is 43.8 feet. Its length is 12.4 feet. What is its width?
Veseljchak [2.6K]

Answer:

9.5 ft

Step-by-step explanation:

12.4 times 2 is 24.8 feet (this is the two lengths combined)

since the garden is 43.8 feet, subtract.  43.8 - 24.8 = 19

lastly, 19 divided by 2 is 9.5.

8 0
3 years ago
Read 2 more answers
Two swimmers start out from opposite ends of a swimming pool(red side and blue side). They cross each other for the first time a
daser333 [38]

Answer:

13 yds

Step-by-step explanation:

the blue side starter (B) swims 29yd in the time it takes the red side starter (R) to swim 21yd

their combined distance, when they meet, is 50yd (length of pool)

 

they pass each other and continue to the ends of the pool (combined distance, 100yd)

they swim towards each other again, and pass a second time (combined distance, 150yd)

at this point, R has swum 63yd (3*21) -- one length plus 13yd

so RS is 13yd from the blue end

7 0
3 years ago
Solve the following equation fro g:2(g-h)=b+4
monitta
2g - 2h = b + 4
2g = b + 4 + 2h
g = (b + 4 + 2h) / 2
4 0
3 years ago
Read 2 more answers
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