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mariarad [96]
3 years ago
8

On a sunny day, if a 36-inch yardstick casts a 21-inch shadow,

Mathematics
1 answer:
dedylja [7]3 years ago
3 0

It would be 288 ft.

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Find the value of x in each figure number 5 please
Stells [14]
So the angle that's next to the 62 is 118. Now that means the other angles have to add up to 62. 62-14= 48 and 48/2 is 24 so X=24. Good luck! :)
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16 increased by twice a number is -24. Find the solution??
marin [14]
<em>The required equation is </em>

<em>2x + 16 = -24</em>
<em>=> 2x = -24 -16</em>
<em>=> 2x = -40</em>
<em>Dividing both sides by 2</em>

<em>x = -20</em>
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The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the
Mumz [18]
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well   \bf v=rw\qquad &#10;\begin{cases}&#10;v=\textit{linear velocity}\\&#10;r=radius\\&#10;w=\textit{angular velocity}\\&#10;----------\\&#10;r=18in\\&#10;w=1302\frac{\pi }{min}&#10;\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}&#10;\\\\\\&#10;v=\cfrac{23436\pi\ in}{min}

now, how much is that in miles/hrs?  well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus   \bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}

notice, after all the units cancellations, you're only left with mi/hrs
4 0
3 years ago
Find the slope between two points ( -2,4) 3,-6)
Ksivusya [100]

Answer:

-1/2

Step-by-step explanation:

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A 3 kg toy car rests st the top of a 0.45 meter ramp. What is its gravitational potential energy?
salantis [7]
<span>gravitational potential energy : P
Gravity : g
Mass : m
height : h

P = mgh  = 3 x 9.8 x 0.45 = 13.23 Joule

Potential energy is work , from the known formula

W = Fd ( work = force x distance ) 

W = P ( in case of potential energy height change)

F is the force acting on the body in case of ideal ramp , the only force acting is the weight of the body

F = mg ( not just <m> as the force is mg (Newton) gravity effect)

d is the displacement in direction of force, as we have considered the force to be the weight not it's component in direction of the ramp , the change in displacement is the change in height so

d = h 

W = Fd = (F = mg) x (d = h) = mgh 

W = mgh = P


</span>

7 0
4 years ago
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