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3 years ago

Como se obtiene el area de un polígono regular?

Mathematics

2 answers:

Vinvika [58]3 years ago

8 0

Answer:

Área de un polígono regular. El área o superficie de un polígono es igual al producto del perímetro por la apotema dividido por dos. El perímetro es la suma de todos los lados.

Step-by-step explanation:

soldier1979 [14.2K]3 years ago

5 0

Answer:

Step-by-step explanation:

El área de un polígono regular se calcula a partir de su perímetro y su apotema. Sea P el polígono regular con N lados, su área es:

Fórmula del área del polígono regular mediante su perímetro

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1 year ago

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Problem 1

<h3>Answer: 6.7</h3>

----------------

Work Shown:

The two points are $(x_1,y_1) = (1,-2)$ and $(x_2,y_2) = (4,4)$

Apply the distance formula to get the following

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (-2-4)^2}\\\\d = \sqrt{(-3)^2 + (-6)^2}\\\\d = \sqrt{9 + 36}\\\\d = \sqrt{45}\\\\d \approx 6.7082039\\\\d \approx 6.7\\\\$

The distance between the two endpoints is roughly 6.7 units. This is the same as saying the segment is roughly 6.7 units long.

======================================================

Problem 2

<h3>Answer: 3.6</h3>

----------------

Work Shown:

We'll use the distance formula here as well.

This time we have the two points $(x_1,y_1) = (3,1)$ and $(x_2,y_2) = (5,-2)$

The distance between them is...

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (1-(-2))^2}\\\\d = \sqrt{(3-5)^2 + (1+2)^2}\\\\d = \sqrt{(-2)^2 + (3)^2}\\\\d = \sqrt{4 + 9}\\\\d = \sqrt{13}\\\\d \approx 3.6055513\\\\d \approx 3.6\\\\$

This distance is approximate.

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