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liberstina [14]
3 years ago
10

Verify this identity: show work cot(x-pi/2)= -tanx

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0
-tan(x) = cot(x - \frac{\pi}{2})
-tan(x) = \frac{cos(x - \frac{\pi}{2})}{sin(x - \frac{\pi}{2})}
-tan(x) = \frac{sin(x)}{-cos(x)}
-tan(x) = -tan(x)

There :).

The most important thing to note here is that cos(x-\frac{\pi}{2}) = sin(x)
and sin(x-\frac{\pi}{2}) = -cos(x)

Normally, over time you end up memorizing these two identities since you use them so often, but proving them is very easy:

cos(x-\frac{\pi}{2}) = cos(x)cos(\frac{\pi}{2}) + sin(x)sin(\frac{\pi}{2}) = cos(x)*0 + sin(x) * 1
= sin(x)

sin(x-\frac{\pi}{2}) = sin(x)cos(\frac{\pi}{2}) - cos(x)sin(\frac{\pi}{2}) = sin(x) * 0 - cos(x) * 1
= -cos(x)
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