Someone help me plz ???

What is the x-intercepts of the graph of y = 12x-5x-2

hammer [34]

Y = 12x - 5x - 2

first simplify the equation by subtracting like terms (in this case):

12x - 5x = 7x

y = 7x - 2

Since you are finding the x, you must isolate the x. Do the opposite of PEMDAS.(Note: because there is a equal sign, what you do to one side, you do to the other)

y = 7x - 2

y (+2) = 7x - 2 (+2)
y + 2 = 7x
(y + 2)/7 = 7x/7

x = (y + 2)/7

x = (y + 2)/7 is your answer

hope this helps

8 0

3 years ago

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Find the number that makes the ratio equivalent to 3:9. 9:?

sesenic [268]

Answer:

27

Step-by-step explanation:

Given the ratio 3 : 9

and 9 : ?

note that 3 × 3 = 9, thus 9 × 3 = 27

3 : 9 = 9 : 27

5 0

3 years ago

NO LINKS!!!!! Write 5 summary for the data below. Show your work.

ankoles [38]

Answer:

$lower \: quartile = \frac{1}{4} \times 8 \\ = {2}^{nd} \\ = 3$

$upper \: quatile = \frac{3}{4} \times 8 \\ = 6 {}^{th} \\ = 7$

$median = \frac{1}{2} \times 8 \\ = 4 {}^{th} \\ = 5$

5 0

3 years ago

BRAINLIEST WILL BE AWARDED!

tatuchka [14]

Answer:

photomath

Step-by-step explanation:

i dont know the answer but photomath is so much easier to get help.

6 0

3 years ago

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A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago