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fiasKO [112]
2 years ago
5

Someone help me plz ???

Mathematics
1 answer:
kirill115 [55]2 years ago
6 0

Answer:

158cm squared

Step-by-step explanation:

Area of triangle=1/2×b×h

Area of rectangular base of prism=l×w

Area of 2 rectangular sides of the prism=l×w

So Total surface area= 1/2×6×5×2)+(8×6)+(8×5×2)=158cm squared

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What is the x-intercepts of the graph of y = 12x-5x-2
hammer [34]
Y = 12x - 5x - 2

first simplify the equation by subtracting like terms (in this case):

12x - 5x = 7x

y = 7x - 2

Since you are finding the x, you must isolate the x. Do the opposite of PEMDAS.(Note: because there is a equal sign, what you do to one side, you do to the other)

y = 7x - 2

y (+2) = 7x - 2 (+2)
y + 2 = 7x
(y + 2)/7 = 7x/7

x = (y + 2)/7


x = (y + 2)/7 is your answer

hope this helps
8 0
3 years ago
Read 2 more answers
Find the number that makes the ratio equivalent to 3:9. 9:?
sesenic [268]

Answer:

27

Step-by-step explanation:

Given the ratio 3 : 9

and 9 : ?

note that 3 × 3 = 9, thus 9 × 3 = 27

3 : 9 = 9 : 27

5 0
3 years ago
NO LINKS!!!!! Write 5 summary for the data below. Show your work.
ankoles [38]

Answer:

lower \: quartile =  \frac{1}{4}  \times 8 \\  =  {2}^{nd}  \\  = 3

upper \: quatile =  \frac{3}{4}  \times 8 \\  = 6 {}^{th}  \\  = 7

median =  \frac{1}{2}  \times 8 \\  = 4 {}^{th}  \\  = 5

5 0
3 years ago
BRAINLIEST WILL BE AWARDED!
tatuchka [14]

Answer:

photomath

Step-by-step explanation:

i dont know the answer but photomath is so much easier to get help.

6 0
3 years ago
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A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
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