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Darya [45]
2 years ago
9

HELP ME OUT PLS!!!!!​

Mathematics
2 answers:
Aloiza [94]2 years ago
8 0
That answer is 64 that is the answer
pantera1 [17]2 years ago
4 0

The Answer Is C. 64, hope I helped

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Plz help me with this
Vanyuwa [196]

Answer:  x = 4

<u>Step-by-step explanation:</u>

6ˣ = 1296

6ˣ = 6⁴

Since they have the same base, set the exponents equal to each other:

x = 4

4 0
3 years ago
Problem: Match each value on the left with the number on the right that includes that value.
Anestetic [448]

Answer:

5 Thousands ⇒ 45,089

8 Hundreds ⇒ 958,823

3 millions ⇒ 3,072,700

2 Ten thousands ⇒ 7,426,580

7 Hundred Thousands ⇒ 752,671

Step-by-step explanation:

Solution:

We need match the numbers with given set of numbers.

Now,

5 thousands ⇒

So we can say that from given set of the numbers we need to find the number 5 belongs in thousands place.

So we can say that the number 5 in thousands place from given of number is ;

5 Thousands ⇒ 45,089

8 Hundreds ⇒

So we can say that from given set of the numbers we need to find the number 8 belongs in hundred place.

So we can say that the number 8 in Hundred place from given of number is ;

8 Hundreds ⇒ 958,823

3 Millions ⇒

So we can say that from given set of the numbers we need to find the number 3 belongs in millions place.

So we can say that the number 3 in Millions place from given of number is ;

3 millions ⇒ 3,072,700

2 Ten thousands ⇒

So we can say that from given set of the numbers we need to find the number 2 belongs in Ten thousands place.

So we can say that the number 3 in Ten Thousands place from given of number is ;

2 Ten thousands ⇒ 7,426,580

7 Hundred thousands ⇒

So we can say that from given set of the numbers we need to find the number 7 belongs in Hundred thousands place.

So we can say that the number 7 in Hundred Thousands place from given of number is ;

7 Hundred Thousands ⇒ 752,671

Hence the matching numbers are

5 Thousands ⇒ 45,089

8 Hundreds ⇒ 958,823

3 millions ⇒ 3,072,700

2 Ten thousands ⇒ 7,426,580

7 Hundred Thousands ⇒ 752,671

6 0
3 years ago
HELP ME PLEASE I AM BEGGING
Inessa05 [86]

Answer:

H

Step-by-step explanation:

well it would be a proportion. so 5 cans per 3 days gives you 5/3. then for the next proportion. it would also be cans over days. so c / 7

5/3 = c/7

answer is H

8 0
3 years ago
Which graph shows the result of dilating this figure by a factor of 4 about the origin? On a coordinate plane, rectangle A B C D
Andrei [34K]

Answer:

Second option: On a coordinate plane, rectangle A'B'C'D' prime has points (-4,4),(12,4),(12,-4),(-4,-4)

(See the graph attached)

Step-by-step explanation:

For this exercise it is importnat to know that a Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) has the same shape as the Pre-Image (which is the original figure before the transformation), but they have different sizes.

In this case, you know that the vertices of the rectangle ABCD ( The Pre-Image)  are the following:

A(-1,1)\\\\B(3,1)\\\\C(3,-1)\\\\D(-1,-1)

Therefore, to find the vertices of the rectangle A'B'C'D' (The Image)  that results of dilating the rectangle ABCD by a factor of 4 about the origin, you need to multiply the coordinates of each original vertex by 4. Then, you get:

A'=((-1)(4),(1)(4))=(-4,4)\\\\B'=((3)(4),(1)(4))=(12,4)\\\\C'=((3)(4),(-1)(4))=(12,-4)\\\\D'=((-1)(4),(-1)(4))=(-4,-4)

Finally, knowing those points, you can identify that the graph that shows the result of that Dilation, is the one attached.

7 0
3 years ago
Read 2 more answers
Match its group with its percentage or mean Using
krok68 [10]

(1)

Mean length of all fish in the sample - \boxed{\sf{\red{6.2}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

=<em> 6.2</em>

(2)

Mean length of adult fish in the sample - \boxed{\sf{\red{8.75}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - \boxed{\sf{\red{4.5}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - \boxed{\sf{\red{40}}}

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - \boxed{\sf{\red{60}}}

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - \boxed{\sf{\red{10}}}

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

<em>% = </em><em>1</em><em>0</em>

7 0
3 years ago
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