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suter [353]
3 years ago
5

Situation- I took time away from preparing for my Quiz competition to help two of my neighbourhood friends for their class exam.

However, when I needed some help with my Science survey, none of them volunteered. I felt hurt and disappointed.
Response
a)No.3
b)No.5
c)No.1
d)No.4​
Chemistry
2 answers:
Evgen [1.6K]3 years ago
6 0

Explanation:

canot understand the question

blsea [12.9K]3 years ago
3 0
Sorry I did not understand the question
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Which Lewis electron-dot diagram is correct for CO2?
Effectus [21]

Answer:

see explanation

Explanation:

The Lewis structure of a substance is otherwise known as its dot electron structure. It gives an immediate picture of the bonding and number of electron pairs in the molecule. The diagram shows only the valence electrons on each of the bonding atoms in the molecule and how they combine to form the molecule under consideration.

The correct Lewis structure for CO2  is shown in the image attached. CO2 has 16 valence electrons. This can be verified by counting the number of dots in the image attached.

3 0
3 years ago
Read 2 more answers
Enthalpy of formation (kJ/mol) C6H12O6(s)-1260 O2 (g)0 CO2 (g)-393.5 H2O (l)-285.8 Calculate the enthalpy of combustion per mole
trapecia [35]

Answer : The enthalpy of combustion per mole of C_6H_{12}O_6 is -2815.8 kJ/mol

Explanation :

Enthalpy change : It is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]

The equilibrium reaction follows:

C_6H_{12}O_6(s)+6O_2(g)\rightleftharpoons 6CO_2(g)+6H_2O(l)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(n_{(CO_2)}\times \Delta H^o_f_{(CO_2)})+(n_{(H_2O)}\times \Delta H^o_f_{(H_2O)})]-[(n_{(C_6H_{12}O_6)}\times \Delta H^o_f_{(C_6H_{12}O_6)})+(n_{(O_2)}\times \Delta H^o_f_{(O_2)})]

We are given:

\Delta H^o_f_{(C_6H_{12}O_6(s))}=-1260kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(6\times -393.5)+(6\times -285.8)]-[(1\times -1260)+(6\times 0)]=-2815.8kJ/mol

Therefore, the enthalpy of combustion per mole of C_6H_{12}O_6 is -2815.8 kJ/mol

6 0
4 years ago
Read 2 more answers
Which of the following is not a type of biomolecule?
Degger [83]

Answer:

Nucleic acids are not considered nutrients. There are thousands of different types of molecules in a cell, but there are only four major classes of biomolecules. These are carbohydrates, lipids, proteins, and nucleic acids. Carbohydrates are compounds such as sugars and starches

Explanation:

5 0
3 years ago
7. What is a meteorite? It is a
Furkat [3]

Answer:

7.

D. remains of meteoroids that hit the Earth

8.

C. icy ball of rock that displays a coma, a fuzzy temporary atmosphere, or a tail

9.

A. silicon, oxygen, and at least one metal

10.

A. They are valuable minerals.

11.A. The resulting cloud would block out sunlight.

12.B. crater

13.A. Asteroid Belt

8 0
3 years ago
Which describes how a turbine works to produce energy for electricity?
masya89 [10]
A. The wind power moves the turbine which, in turn, produces electricity.
6 0
3 years ago
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