Which of the situations below describes an ethical dilemma related
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Answer:
How many grams Acetic Acid in 1 mol? The answer is 60.05196.
We assume you are converting between grams Acetic Acid and mole?
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Explanation:
You can view more details on each measurement unit:
molecular weight of Acetic Acid or mol
The molecular formula for Acetic Acid is CH3COOH.
The SI base unit for amount of substance is the mole.
1 grams Acetic Acid is equal to 0.016652245821785 mole.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between grams Acetic Acid and mole.
Examples
1 grams Acetic Acid to mol = 0.01665 mol
10 grams Acetic Acid to mol = 0.16652 mol
20 grams Acetic Acid to mol = 0.33304 mol
30 grams Acetic Acid to mol = 0.49957 mol
40 grams Acetic Acid to mol = 0.66609 mol
50 grams Acetic Acid to mol = 0.83261 mol
100 grams Acetic Acid to mol = 1.66522 mol
200 grams Acetic Acid to mol = 3.33045 mol
Answer:
2.5 % butane, 42.2 % pentane and 55.3 % hexane
Explanation:
Hello,
In this case, the mass balance for each substance is given by:
Whereas accounts for the fractions at the outlet distillate and
for the fractions at the outlet bottoms. Moreover, with the 90 % recovery of butane, we can write:
So we can compute the product of the molar fraction of butane at the distillate by total distillate flow by assuming a 100-mol feed:
The total distillate flow:
And the total bottoms flow:
Next, by using the mass balance of butane, we compute the molar fraction of butane at the bottoms:
Then, the molar fraction of pentane and hexane:
Therefore, the molar composition of the bottom product is 2.5 % butane, 42.2 % pentane and 55.3 % hexane.
NOTE: notice the result is independent of the value of the assumed feed, it means that no matter the basis, the compositions will be the same for the same recovery of butane at the feed, only the flows will change.
Regards.