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3 years ago

What is the happens in electrolysis if the electrolyte solidifies?

1 answer:

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Answer: For example, if electricity is passed through molten lead bromide, the lead bromide is broken down to form lead and bromine. This is what happens during electrolysis: Positively charged ions move to the negative electrode during electrolysis. ... Negatively charged ions move to the positive electrode during electrolysis.

Explanation:

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Which two compounds are molecules which both contain a double bond

Mademuasel [1]

Answer:

Double bond

Chemical compounds with double bonds.

Ethylene Carbon-carbon double bond.

Acetone Carbon-oxygen double bond.

Dimethyl sulfoxide Sulfur-oxygen double bond.

Diazene Nitrogen-nitrogen double bond.

Explanation:

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3 years ago

How do ionic bonds form in binary compounds?<br><br> (from discovery education)

Nookie1986 [14]

Answer:

Ionic bonding is the complete transfer of valence electron(s) between atoms and is a type of chemical bond that generates two oppositely charged ions. By losing those electrons, these metals can achieve noble-gas configuration and satisfy the octet rule.

Explanation:

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3 years ago

In rabbits, the gene for black fur is dominant (F), but the gene for white fur

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A white rabbit would therefore have (ff)

If a trait is recessive, then it can only be expressed if both alleles (individual letters) are recessive (lowercase).

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3 years ago

What solutions do we need to work on to get accurate results?<br> A) concentrated<br> B) diluted

Bess [88]

Answer:

A

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3 years ago

Suppose 10.0 mL of 2.00 MNaOH is added to (a) 0.780 L of pure water and (b) 0.780 L of a buffer solution that is 0.682 Min butan

katrin2010 [14]

Answer:

a) pH will be 12.398

b) pH will be 4.82.

Explanation:

a) The moles of NaOH added = molarity X volume (L) = 2 X 0.01 = 0.02 moles

The total volume after addition of pure water = 0.780+0.01 = 0.79 L

The new concentration of /NaOH will be:

$molarity=\frac{molesofsolute}{volumeofsolution}=\frac{0.02}{0.79}=0.025M$

the [OH⁻] = 0.025

pOH = -log [OH⁻] = 1.602

pH = 14 -pOH = 12.398

b) The buffer has butanoic acid and butanoate ion.

i) Before addition of NaOH the pH will be calculated using Henderson Hassalbalch's equation:

$pH=pKa+log\frac{[salt]}{[acid]}$

pKa= $-logKa=-log(1.5X10^{-5})=4.82$

ii) on addition of base the pH will increase.

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4 years ago

What is the happens in electrolysis if the electrolyte solidifies?​

What is the happens in electrolysis if the electrolyte solidifies?