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3 years ago

I've been stuck on this question for so long

Mathematics

1 answer:

velikii [3]3 years ago

6 0

If you reflect the rectangle across either the horizontal or the vertical line going straight through the middle, you will reflect it onto itself (see image).

The equation for the horizontal line is y = -1. The equation for the vertical line is x = -1.

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What are the steps to understanding this problem as well as the answers.

svetlana [45]

Step-by-step explanation:

$\frac{1}{3 + 4i} \times \frac{3 - 4i}{3 - 4i} = \frac{3 - 4i}{25} = \frac{ 3}{25} - \frac{4i}{25}$

$\frac{1}{3 - 4i} \times \frac{3 + 4i}{3 + 4i} = \frac{3 + 4i}{25} = \frac{ 3}{25} + \frac{4i}{25}$

1+0i

$\frac{3 - 4i}{3 + 4i} \times \frac{3 - 4i}{3 - 4i} = \frac{ - 7 - 24i}{25} = - \frac{7}{25} - \frac{24i}{25}$

3 - 4i

$\frac{3 + 4i}{3 - 4i} \times \frac{3 + 4i}{3 + 4i} = \frac{ - 7 + 24i}{25} = - \frac{7}{25} + \frac{24i}{25}$

4 0

3 years ago

Write 0.7 as a fraction. Show your work

Reptile [31]

0.7 is seven tenths.

Seven tenths as a fraction is 7/10.

Hope this helps!

5 0

3 years ago

Read 2 more answers

If 25 students took an exam and 4 of them failed, what percent of them passed?

lisabon 2012 [21]

If 25 students took an exam and 4 of the students that took the exam failed, what percent of the students passed?

To find out how many students passed, we can subtract 4 from 25 and we will get a difference of 21.

The fraction $\frac{21}{25}$ represents the number of students who passed the exam out of all the students.

To find out what percent of the students passed, we can turn $\frac{21}{25}$ into a percent.

21 ÷ 25 = 0.84

0.84 × 100 = 84%

Therefore, 84% of the students who took the exam passed.

5 0

4 years ago

Combining like term 6k+7k

Nadya [2.5K]

13k is the answer :)

8 0

3 years ago

Please help with math please.

jonny [76]

Subtract the constant vector that is on the left. The arithmetic applies to corresponding elements of the vectors.

$A=\left[\begin{array}{cccc}0&1&-2&3\end{array}\right] -\left[\begin{array}{cccc}11&17&-8&13\end{array}\right]\\\\A=\left[\begin{array}{cccc}-11&-16&6&-10\end{array}\right]\\\\a_{11}=-11\\a_{12}=-16\\a_{13}=6\\a_{14}=-10$

5 0

3 years ago

I've been stuck on this question for so long​

I've been stuck on this question for so long