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Elena L [17]
2 years ago
15

14.4x - 28.2 > 36.6

Mathematics
1 answer:
Musya8 [376]2 years ago
4 0

Answer:

x > 4.5

Step-by-step explanation:

Given the inequality :

14.4x - 28.2 > 36.6

Collect like terms

14.4x > 36.6 + 28.2

14.4x > 64.8

Divide both sides by 14.4

x > 64.8 / 14.4

x > 4.5

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2 years ago
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A corporate bond has a coupon rate of 5.5 percent, a $1,000 face value, and matures three years from today. The corporation is i
melomori [17]

Answer:

= \frac{\frac{75}{100}\times 1000 + \frac{25}{100} \times \frac{60}{100}\times 1000  }{(1+\frac{15}{100})^3 }

=\frac{0.75\times 1000 + 0.25\times 0.60 \times 1000}{(1+0.15)^3}

=\frac{750+0.25\times 0.60\times 1000}{1.15^3} \\\\=\frac{750+150}{1.520875} =\frac{900}{1.520875} \\\\=591.76

Step-by-step explanation:

= (probability of entire face value paid*face value+probability of entire face value not paid*percent of face value paid*face value)/(1+discount rate)^years to maturity

probability of entire face value paid = 75%

face value = 1000

probability of entire face value not paid = 25%

percent of face value paid= 60%

discount rate = 15%

years to maturity  = 3

= \frac{\frac{75}{100}\times 1000 + \frac{25}{100} \times \frac{60}{100}\times 1000  }{(1+\frac{15}{100})^3 }

=\frac{0.75\times 1000 + 0.25\times 0.60 \times 1000}{(1+0.15)^3}

=\frac{750+0.25\times 0.60\times 1000}{1.15^3} \\\\=\frac{750+150}{1.520875} =\frac{900}{1.520875} \\\\=591.76

6 0
2 years ago
What is the answer for b?
olchik [2.2K]
B=180-(73+69)=38 degrees
7 0
2 years ago
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Find the area lying outside r=6cos(theta) and inside r=3+3cos(theta)
Sloan [31]
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b... 

<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>

<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>

<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
7 0
3 years ago
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