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Nonamiya [84]
2 years ago
10

Which statement about rigid transformations is true?

Mathematics
1 answer:
Tju [1.3M]2 years ago
5 0

Answer:

The answer is B because it is only the measure of the polygon

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Answer?????????????????
ANTONII [103]
So the angle A on the first diamond corresponds with angle Q, angle B with angle S, angle C with angle R, and angle D with angle P. So if angle D correspond (equals) angle P then x+34=97 and if angle R corresponds with C then 3y-13=83. From there just do some basic algebra to find the x and y values. 
5 0
3 years ago
95% of the students passed the math final exam. If 200 students take the final, how many students passed? Steps greatly apprecia
Anit [1.1K]

Answer:

190 students

Step-by-step explanation:

Set up a proportion:

95/100 = x/200

Cross multiply:

100x = 19000

Simplify:

x = 190 students

3 0
3 years ago
Water has a freezing point of 32 degrees. Murcury has a freezing point that is 70 degrees lower. What is the freezing point of m
Mekhanik [1.2K]

Answer:

-38 degrees

Step-by-step explanation:

32-70

= -38

8 0
3 years ago
What is the area surface?
Rus_ich [418]

Answer:

The total area of the surface of a three-dimensional object.

Step-by-step explanation:

6 0
3 years ago
Solving Rational Inequalities and use sign diagram to sketch the graph. Image attached for better understanding.
Digiron [165]

Answer:

x ∈ (-∞, -1) ∪ (1, ∞)

Step-by-step explanation:

To solve this problem we must factor the expression that is shown in the denominator of the inequality.

So, we have:

x ^ 2-1 = 0\\x ^ 2 = 1

So the roots are:

x = 1\\x = -1

Therefore we can write the expression in the following way:

x ^ 2-1 = (x-1)(x + 1)

Now the expression is as follows:

\frac{(x-2) ^ 2}{(x-1) (x + 1)}\geq0

Now we use the study of signs to solve this inequality.

We have 3 roots for the polynomials that make up the expression:

x = 1\\x = -1\\x = 2

We know that the first two are not allowed because they make the denominator zero.

Observe the attached image.

Note that:

(x-1)\geq0 when x\geq-1

(x + 1)\geq0 when x\geq1

and

(x-2) ^ 2 is always \geq0

Finally after the study of signs we can reach the conclusion that:

x ∈ (-∞, -1) ∪ (1, 2] ∪ [2, ∞)

This is the same as

x ∈ (-∞, -1) ∪ (1, ∞)

6 0
3 years ago
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