3 years ago

Which statement is true?

Mathematics

1 answer:

Aneli [31]3 years ago

6 0

The letter has both reflection and rotation symmetry

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Solve for [0,2pi): 3sin^2x-6sinx=0

Ainat [17]

Given the equation :

$3\sin ^2x-6\sin x=0$

Let: y = sin x

So,

$\sin ^2x=y^2$

the given equation will be:

$3y^2-6y=0$

Solve for y, take 3y as a common:

$\begin{gathered} 3y(y-2)=0 \\ 3y=0\rightarrow y=0 \\ y-2=0\rightarrow y=2 \end{gathered}$

so,

$\begin{gathered} y=0\rightarrow\sin x=0\rightarrow x=0or\pi \\ y=2\rightarrow\sin x=2 \end{gathered}$

Note: the range of sine function is [ -1, 1]

So, sin x = 2 ( is rejected)

So, the answer will be: x ={ 0 , pi }

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1 year ago

(1/2)^3-(1/4)^2+1/2 help?

mrs_skeptik [129]

Answer:

$(\frac{1}{2}) ^{3} - (\frac{1}{4} )^{2} +\frac{1}{2} = \frac{9}{16}$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given

$(\frac{1}{2}) ^{3} - (\frac{1}{4} )^{2} +\frac{1}{2}$

= $\frac{1}{8} - \frac{1}{16} + \frac{1}{2}$

$=\frac{2-1}{16} + \frac{1}{2}$

= $\frac{1}{16} + \frac{1}{2}$

= $\frac{1+8}{16}$

= $\frac{9}{16}$

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3 years ago

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mariarad [96]

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kiruha [24]

Answer:

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Step-by-step explanation:

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3 years ago