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3 years ago

15

An exam has two probability problems, 1 and 2. If 37% of the students solved problem 1 and 12% of the students solved both probl

ems 1 and 2, what is the percent of students who solved problem 2 given that they solved problem 1

1 answer:

yan [13]3 years ago

3 0

Answer:

63%

Step-by-step explanation:

37% did not solve problem 2

100% - 37% = 63%

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N is the set of integers that are greater than - 3 and less than 2.

Schach [20]

The given set is {-1,0,1,2,3,4,5}
(notice the -2 and 6 are excluded)

the subset which contain positive factors of 5 is {1,5}

so the complement set would be
{-1,0,2,3,4) which matches with b)

4 0

3 years ago

A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for $x$ days.

So, for $x$ days the total expense = $360

<em>Thus the daily expense in dollars can be given by</em> = $\frac{360}{x}$

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

<em>Tour duration now</em> = $(x+4)$ days

On extension, his daily expense is cut by $3

<em>New daily expense in dollars </em>= $(\frac{360}{x}-3)$

Total expense in dollars can now be given as: $(x+4)(\frac{360}{x}-3)$

Simplifying by using distribution (FOIL).

$(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))$

$360-3x+\frac{1440}{x}-12$

$348-3x+\frac{1440}{x}$

We know total expense remains the same which is = $360.

So, we have the equation as:

$348-3x+\frac{1440}{x}=360$

Multiplying each term with $x$ to remove fractions.

$348x-3x^2+1440=360x$

Subtracting $348x$ both sides

$348x-348x-3x^2+1440=360x-348x$

$-3x^2+1440=12x$

Dividing each term with -3.

$\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}$

$x^2-480=-4x$

Adding $4x$ both sides.

$x^2+4x-480=-4x+4x$

$x^2+4x-480=0$

Solving using quadratic formula.

For a quadratic equation: $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging in values from the equation we got.

$x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}$

$x=\frac{-4\pm\sqrt{16+1920}}{2}$

$x=\frac{-4\pm\sqrt{1936}}{2}$

$x=\frac{-4\pm44}{2}$

So, we have

$x=\frac{-4+44}{2}$ and $x=\frac{-4-44}{2}$

$x=\frac{40}{2}$ and $x=\frac{-48}{2}$

∴ $x=20$ and $x=-24$

Since number of days cannot be negative, so we take $x=20$ as the solution for the equation.

Thus, the original duration of the tour = 20 days

6 0

3 years ago

0.23 divided by 5.05 explain with steps

Elden [556K]

Answer:

Step-by-step explanation:

\mathrm{Multiply\:the\:numerator\:and\:denominator\:by:}\:100

\mathrm{Multiply\:the\:quotient\:digit}\:\left(0\right)\:\mathrm{by\:the\:divisor}\:505

\mathrm{Subtract}\:0\:\mathrm{from}\:23

3 0

3 years ago

Line segment MN is graphed in the first and second quadrants of a coordinate plane. The segment is translated 2 units up, then r

Ksju [112]

Answer:

Step-by-step explanation:

Since the line segment is only being translated and reflected it would still maintain its length. This is pretty much the only characteristic that would remain the same as te original line segment. It would not maintain the same x-axis positions for both endpoints of the line segment. This is because when it is translated 2 units up it is only moving on the y-axis and not the x-axis. But when it is reflected over the y-axis the endpoints flip and become the opposite values.

6 0

3 years ago

$14.00 for 7 minutes<br> Unit rate

babunello [35]

Answer:

$2/min

Step-by-step explanation:

14 ÷ 7 = 2

Therefore, $2 per minute.

5 0

3 years ago

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