An exam has two probability problems, 1 and 2. If 37% of the students solved problem 1 and 12% of the students solved both probl
1 answer:
You might be interested in
Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
_____
* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
Solve by substitution
Just plug in y=-x-1 into y+x=3
So we get:
Simplify that:
And since that is not true, that means this system of equations has no solutions!
Just plug in y=-x-1 into y+x=3
So we get:
Simplify that:
And since that is not true, that means this system of equations has no solutions!