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4 years ago

What simplified ratio correctly compares 10,000 centimeters to 1000 meters?

Mathematics

2 answers:

-BARSIC- [3]4 years ago

8 0

the awnser to this question is 1:10

Andre45 [30]4 years ago

6 0

Your answer to that question would be

1:10

Hope this helped!

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A parks and recreational board in Birch County is interested in estimating the proportion of its residents in favor of having mo

ankoles [38]

Answer:

Step-by-step explanation:

Trust me.

I just did it.

5 0

4 years ago

Urgent help needed. Will mark you brainlest when correct

posledela

Question 7: Option (4)

$A=(3/8)^2=\frac{9}{64}$

Question 8: Option (3)

$A=\frac{1}{2}(17)(9)=76.5$

Question 9: Option (2)

$A=\pi(10)^2 \approx 314$

7 0

2 years ago

The ratio of yellow blue and red balloons is 2:3:2 respectively. If the total number is 28 is many yellow balloons are there

Phoenix [80]

Answer:

Step-by-step explanation:

The ratio of yellow balloons to the total is ...

... 2:(2+3+2) = 2/7

This fraction of 28 balloons is ...

... (2/7)·28 = 56/7 = 8 . . . . yellow balloons

8 0

3 years ago

HELPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

olga55 [171]

Same solution.

volume = 1/3(8x6)(5) = 16x5 = 80cm^3

answer: 80cm^3

4 0

3 years ago

Determine whether the integral is convergent or divergent. [infinity] 7 e−1/x x2 dx convergent divergent Changed: Your submitted

inessss [21]

I suppose the integral could be

$\displaystyle\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx$

In that case, since $-\frac1x\to0$ as $x\to\infty$ , we know $e^{-1/x}\to1$ . We also have $\left(e^{-1/x}\right)'=\frac{e^{-1/x}}{x^2}>0$ , so the integral is approach +1 from below. This tells us that, by comparison,

$\displaystyle\frac{e^{-1/x}}{x^2}\le\frac1{x^2}\implies\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx\le\int_7^\infty\frac{\mathrm dx}{x^2}$

and the latter integral is convergent, so this integral must converge.

To find its value, let $u=-\frac1x$ , so that $\mathrm du=\frac{\mathrm dx}{x^2}$ . Then the integral is equal to

$\displaystyle\int_{-1/7}^0e^u\,\mathrm du=e^0-e^{-1/7}=1-\frac1{\sqrt[7]{e}}$

4 0

4 years ago