I think the answer is 37.7
Answer:
The width of member is as follows:
b = 3 ft
b = 3 × 12 in.
b= 36 in.
The depth of member is as follows:
d = 8 ft
d = 8 × 12 in.
d=96 in.
Since the structure used is Douglas fir-Larch lumber of size 3 × 8 size. Hence, tensile strength, f =1000 psi
Calculate the net area of the member as follows:
A = (b - ∅) × d
A= (36 - 7/8) × 96

Calculate the maximum axial tensile load by ASD method as follows:
P = f × A
P = 1000 x 3372
P = 3372000 lbs
P = 3372 kips
Answer:
y = x - 3
<h3>How I know I'm correct:</h3>
if you plug in the numbers from the table, it checks out.
y = x - 3
0 = 3 - 3
0 = 0
y = x - 3
1 = 4 - 3
1 = 1
y = x - 3
2 = 5 - 3
2 = 2
and so on
Answer:
y
=
−
41
−
√
3165
2
,
−
41
+
√
3165
2
Decimal Form:
y
=
7.62916635
…
,
−
48.62916635
…
Step-by-step explanation:
The fraction is 4/20 for #2.