Y’’(x)= 6x + 1
y’(x)= 3x^2 + x + 2
y(x)= x^3 + 1/2x^2 + 2x + 5
Answer: 0.0170
Step-by-step explanation:
Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.
i.e.
We assume the distribution of amounts purchased follows the normal distribution.
Sample size : n=50
Let be the sample mean.
Formula :
Then, the probability that the sample mean is at least $25.00 will be :-
Hence, the likelihood the sample mean is at least $25.00= 0.0170
I think it would be 12(2-3)
Hope this helps!
Answer:
1/7
Step-by-step explanation:
there are 7 number possibilities 0,1,2,3,4,5,6.
so if they each have an equal probability the answer is 1/7