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3 years ago

Find an equation of the line passing through each of the following pairs of points.

1 answer:

5 0

To find the equation of the line we will need to find slope and the y-intercept.

Given: (-3,9), (-3,-5)

What we know:
slope=m=(y2-y1)/(x2-x1)
m=(-5-9)/9-3-(-3))=-14/0
m=undefined

When slope=m is undefined we have an a line x=-3. That means that for every y the x value is always -3. This line x=-3 is a vertical line on the graph at -3.

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Harriet earns the same amount of money each day. Her gross pay at the end of 7 work days is 35h + 56 dollars. Which expression r

Alex_Xolod [135]

Answer:

Gross pay per days is 5h+8 dollars

Step-by-step explanation:

we are given

total gross pay =35h+56 dollars

total number of days =7

we know that

gross pay per day = ( total gross pay)/(total number of days)

we can plug values

gross pay per day is

$=\frac{35h+56}{7}$

we can simplify it

$=\frac{7(5h+8)}{7}$

$=5h+8$

7 0

3 years ago

Read 2 more answers

Round 51.78 to the greatest number.

soldier1979 [14.2K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

1. What are two other ways you could rewrite 50%?

NNADVOKAT [17]

0.5 is the first way

1/2 is the second way

50% is the third way.

Hope that helps bud :).

8 0

2 years ago

If the cos 30° = square root 3 over 2, then the sin 60° = _____. 0, because the angles are complementary 1 over 2, because the a

leva [86]

Well, the answer would be square root of 3 over 2 because of the unit circle. So, the answer choice should be which ever one involved square root 3 over 2

3 0

3 years ago

Read 2 more answers

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$