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ddd [48]
3 years ago
13

Find the missing variable. Show all work to receive full credit! 8 36° Х

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
4 0

Answer:

vsbs.

Step-by-step explanation:

vdgs sus zh zh sh sbs. susvudbjd is sus he she bunny can come go to do so to do so I'm to text to do so I'm done em thanksgsvsvs hsvdu come for v roll also duck got v until v you v yo

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Under which of the following conditions will the FIFO method of process costing result in the same amount of cost being transfer
Strike441 [17]

Answer:

I hope you have a wonderful day!

Step-by-step explanation:

I hope this makes your day :))

8 0
3 years ago
Read 2 more answers
Chord AC intersects chord BD at point P in circle Z.
Alik [6]

In this question, we have to use the intersecting chord theorem, and the formula which is

AP * CP = BP * DP

In the given circle, values of AP, CP and DP are 12m, 6m and 5m respectively .

Substituting the values in the formula, we will get

12*6 = 5BP

Dividing both sides by 5

BP = \frac{72}{5} = 14.4 m

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3 years ago
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What is the probability help me ,1.)3/72 2.)3/20,3.)3/10,4.)17/20
cricket20 [7]

Answer:

3/10

Step-by-step explanation:

  1. add 7+4+6+3=20
  2. the take how many times both coins landed on heads which is 6 and put the 6 over 20
  3. then divide by 2 because 2 can go into both 6 and 20
  4. and you end up with 3/10 which you can't simplify any more.
8 0
3 years ago
A certain type of automobile battery is known to last an average of 1110 days with a standard deviation of 50 days. If 100 of th
GalinKa [24]

Answer:

a. P(1104<X[bar]<1110) =  0.3849

b. P(X[bar]>1116) = 0.1151

c. P(X[bar]<940) = 0

Step-by-step explanation:

Hello!

Your study variable is X: "length of life of a battery" (days)

These batteries have a known lifetime average μ: 1110 days and a standard deviation δ:50 days.

To calculate the probabilities I'll apply the Central Limit Theorem, and since the sample is big enough (n>30), approximate the distribution of the sample mean to normal X[bar]≈N(μ;δ²/n) and use the standardization to the Z-distribution to calculate each probability.

a. The average is between 1104 and 1110

P(1104<X[bar]<1110) = P(X[bar]<1110) - P(X[bar]<1104)

= P(Z<(1110-1110)/(50/√100) - P(Z<(1104-1110)/(50/√100))

=P(Z<0) - P(Z<-1.2) = 0.5 - 0.1151 = 0.3849

b. The average is greater than 1116

P(X[bar]>1116) = 1 - P(X[bar]≤1116) = 1 - P(Z≤(1116-1110)/(50/√100))

=1 - P(Z≤1.2) = 1 - 0.8849 = 0.1151

Since the Z table accumulates from left, this means, the probability values it gives are P(Z), to calculate the values ​​above a certain number, you have to subtract from 1 (the highest possible cumulative probability value) all the cumulative probability that is below that number.

c. The average is less than 940.

P(X[bar]<940) = P(Z<(940-1110)/(50/√100)) = P(Z<-34) = 0

I hope you have a SUPER day!

5 0
3 years ago
Express as functions of positive acute angles:
prisoha [69]
1. Sin 240 degree = -sin ( 240 -180 degree) = -sin (60 degree)
2. Tan 130 degree = -tan ( 180 - 130 degree) = -tan 50 degree
3. sec 305 degree = sec ( 360 - 305 degree) = sec (55 degree)
4. cos 95 degree = -<span>cos (180 - 95 degree ) = -cos 85 degree</span>
5. csc 185 degree = -sin 5 degree
4 0
3 years ago
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