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Bad White [126]
3 years ago
5

NEED HELP PLZ HELP!!!!! What is the answer?

Mathematics
2 answers:
allsm [11]3 years ago
4 0
The answer is 300 total apples
lakkis [162]3 years ago
4 0
I would say "300 apples". (15 x 5 = 75 and 75 x 4 = 300). So 300 apples. :)
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A circle has a radius of 4 x^3 y^5 cm. The area of a circle can be found using A equals pi r^2
GrogVix [38]

Answer:

Step-by-step explanation:

There are two other important distances on a circle, the radius (r) and the diameter (d). The radius, the diameter, and the circumference are the three defining aspects of every circle. Given the radius or diameter and pi you can calculate the circumference. The diameter is the distance from one side of the circle to the other at its widest points. The diameter will always pass through the center of the circle. The radius is half of this distance. You can also think of the radius as the distance between the center of the circle and its edge.

This diagram shows the circumference, diameter, center, and radius on a circle.

4 0
3 years ago
What is the area of this trapezoid HELP PLEASE
Zepler [3.9K]

Answer:

Step-by-step explanation:

The answer is 44

6 0
3 years ago
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The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
2 years ago
Answer in factored form 13+14m+m^2
natta225 [31]
<span>Solution


m = {-13, -1}</span>
5 0
3 years ago
Read 2 more answers
Need answer 25 and answer 27
UNO [17]

\\ \bull\tt\dashrightarrow \dfrac{-3}{8}x-20+2x>6

\\ \bull\tt\dashrightarrow \dfrac{-3}{8}x+2x=6+20=26

\\ \bull\tt\dashrightarrow \dfrac{-3+16}{8}x=26

\\ \bull\tt\dashrightarrow \dfrac{13}{8}x=26

\\ \bull\tt\dashrightarrow x=26\times \dfrac{8}{13}

\\ \bull\tt\dashrightarrow x=8(2)=16

#27

\\ \bull\tt\dashrightarrow 0.5x-4-2x\leqslant 2

\\ \bull\tt\dashrightarrow 0.5x-2x\leqslant=2+4=6

\\ \bull\tt\dashrightarrow -1.5x\leqslant 6

\\ \bull\tt\dashrightarrow x\leqslant\dfrac{6}{-1.5}

\\ \bull\tt\dashrightarrow x\leqslant 4

8 0
3 years ago
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