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77julia77 [94]
2 years ago
8

Please help me solve this challanging question 9 (step by step sulotion) 50 points!

Mathematics
1 answer:
defon2 years ago
8 0

9514 1404 393

Answer:

  10

Step-by-step explanation:

Let L and T represent the initial amounts that Leo and Theo had. Let n represent the number of bills exchanged in the first exchange. Then we have ...

  L -20n +50n = T -50n +20n . . . . after the first exchange, each has the same

After the second exchange, amounts trade places:

  (L +30n) +6(50) = T

Substituting this into the first equation, we get ...

  L +30n = ((L +30n) +300) -30n

  30n = 300

  n = 10

Leo gave Theo ten $20 bills.

_____

<em>Comment on the amounts</em>

Theo started with $600 more than Leo, including exactly 16 $50 bills. Leo had at least 10 $20 bills, so he could make the initial exchange. Whatever initial amount Leo had in excess of that $200 was matched in Theo's initial amount, but Theo must have had that excess in $20 bills only. For example, Leo may have started with $300 as 10×$20 +2×$50, but Theo's initial $900 would need to be 5×$20 +16×$50.

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2 years ago
If Josie runs a 25-mile race in 5 hours and Greta runs a 18-mile race in 4 hours. Who runs at a FASTER pace?
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Step-by-step explanation:

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Dafna11 [192]

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8 0
2 years ago
A company's profit C (in thousands of dollars) can be modeled by the polynomial function C = - 5x ^ 3 + 6x ^ 2 + 15x , where x i
steposvetlana [31]

Answer:

849 items.

Step-by-step explanation:

Given that the profit C (in thousands of dollars) for x thousands of items related as

C = - 5x ^ 3 + 6x ^ 2 + 15x \\\\\Rightarrow -5x^3+6x^2+15x -C=0\cdots(i)

As the profit is $14,000 for producing 2000 items, so

C= 14 thousand dollars and

x= 2 thousand items.

Putting C= 14 in the equation ( we have),

-5x^3+6x^2+15x -14=0\cdots(ii)

Now, x=2 is one of the solutions to the equation (ii), so (x-2) is a factor of the equation (ii), we have

(x-2)(-5x^2-4x+7)=0 \\\\\Rightarrow x-2=2 \; or \; -5x^2-4x+7=0

We have the given solution for x-2=0, so sloving -5x^2-4x+7=0 for other solutions.

-5x^2-4x+7=0 \\\\\Rightarrow x= \frac {-(-4)\pm \sqrt {(-4)^2-4\times (-5)7}}{2\times (-5)} \\\\\Rightarrow x= \frac {4\pm \sqrt {156}}{2\times (-5)} \\\\\Rightarrow x= \frac {4\pm 12.49}{2\times (-5)} \\\\\Rightarrow x = \frac {4+ 12.49}{2\times (-5)}, \frac {4- 12.49}{2\times (-5)} \\\\\Rightarrow x = -1.649, 0.849

As the number of items cant be negative, so x= 0.849 thousand is the other number of items.

Hence, the other number of items for the same profit is 849 items.

4 0
3 years ago
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