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Ne4ueva [31]
2 years ago
13

Please help i will give brainly :

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
5 0

1) The x-axis represents the energy (E), in joules. The y-axis represents the amplitude (x), in milimeters.

2) The curve depicts an <em>monotonous decrecent</em> rate of change.

3) The amplitude is directly proportional to the root square of the energy.

<h3>How to analyze a graph relationship between two variables</h3>

In this question we have a relationship between two variables, in which we must apply principles of <em>functional</em> analysis to respond three questions presented in the statement.

Now we proceed to answer the three questions below:

  1. <em>What is on the x-axis? The y-axis?</em> R/ The x-axis represents the energy (E), in joules. The y-axis represents the amplitude (x), in milimeters.
  2. <em>How would you describe the rate of change of the line?</em> R/ The curve depicts an <em>monotonous decrecent</em> rate of change, that is, the slope converges to zero when the energy tends to infinite.
  3. <em>What does this tell you about the relationship between amplitude and energy?</em> R/ The curve show a strong similarity with a function of the form x = A\cdot \sqrt{E}. Hence, the amplitude is directly proportional to the root square of the energy.

To learn more on functions, we kindly invite to check this verified question: brainly.com/question/12431044

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<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

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Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

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\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

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\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

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\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

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