This is an exponential growth problem. Exponential growth can be expressed mathematically in the following way:
.
Parameter a presents initial amount.
Parameter r is percentage increase.
Parameter t is time.
An equation that would describe given problem is:
t is the time in years.
I attached the graph of this function.
A.) 0.35x + 42 ≤ 70
She wants the truck for one day, which will cost $45. We don't know how far the truck is traveling so that is the variable. She cannot spend more than $70, since that is her budget.
b.) Solve for x using the above equation:
0.35x + 42 ≤ 70
0.35x ≤ 28
x ≤ 80
Judy can drive 80 miles
Answer:
Both plans would cost $100 if 6 gigabytes of data are used.
Explanation:
From the question, the system of equation are correctly represented by using small letter c to represent the total cost in dollars for both equations as already assumed in the question as follows:
c = 52 + 8d ........................... (1)
c = 82 + 3d ........................... (2)
Since c is common to both, equations (1) and (2) can therefore be equated and d solved for as follows:
52 + 8d = 82 + 3d
8d - 3d = 82 - 52
5d = 30
d = 30 / 5
d = 6
Substituting d = 6 into equation (1), we have:
c = 52 + (8 * 6)
c = 52 + 48
c = 100
Since d = 6 and c = 100, it therefore implies that both plans would cost $100 if 6 gigabytes of data are used.
Answer: 500$
Step-by-step explanation: 150 is 70% off the ORIGINAL price, so 150 is actually 30% off. Divide everything by 3 and you get 50$ = 10%. Multiple 50 by 10 and you get 500, your answer.
