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3 years ago

Basic design elements include (Check 7)

Physics

1 answer:

myrzilka [38]3 years ago

4 0

Answer: depth, shade, fragrance

Explanation:

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What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.

julia-pushkina [17]

<h2>Answer: 34.78 m/s</h2>

Explanation:

The momentum $p$ is given by the following equation:

$p=m.V$ (1)

Where:

$m$ is the mass of the object

$V$ is the velocity of the object

Finding the velocity from (1):

$V=\frac{p}{m}$ (2)

$V=\frac{4000kg.m/s}{115kg}$

<u>Finally:</u>

$V=34.78m/s$ >>>This is the velocity of the object

4 0

3 years ago

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A 27.0-g object moving to the right at 21.5 cm/s overtakes and collides elastically with a 11.0-g object moving in the same dire

7nadin3 [17]

Answer:

final speed of the first object: 17.73 cm/s

final speed of the second object: 24.23 cm/s

Explanation:

Data:

mass of the first object, m1 = 27.0 g

mass of the second object, m2 = 11.0 g

initial speed of the first object, v1i = 21.5 cm/s

initial speed of the second object, v2i = 15 cm/s

final speed of the first object, v1f = ? cm/s

final speed of the second object, v2f = ? cm/s

Elastic collisions formula:

v1f = (m1 - m2)/(m1 + m2) * v1i + 2*m2/(m1 + m2) * v2i

v1f = (27 - 11)/(27 + 11) * 21.5 + 2*11/(27 + 11) * 15

v1f = 17.73 cm/s

v2f = 2*m1/(m1 + m2) * v1i + (m2 - m1)/(m1 + m2)*v2i

v2f = 2*27/(27 + 11) * 21.5 + (11 - 27)/(27 + 11)*15

v2f = 24.23 cm/s

8 0

3 years ago

IRISSAK [1]

Answer:

The basic unit of matter is atoms

8 0

3 years ago

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An archer pulls her bow string back 0.40 m by exerting a force that increases uniformly from zero to 230 N. (a) What is the equi

Naya [18.7K]

Hi there!

Using Hooke's Law:
$F = kx$

F = Force (N)
k = Spring constant (N/m)
x = displacement from equilibrium

We are given the force and displacement, so solve for 'k':
$k = \frac{F}{x}\\
\\
k = \frac{230}{0.4} = \boxed{575 N/m}$

6 0

3 years ago

If no friction acts on a diver during a dive, then which of the following statements is true? A) The total mechanical energy of

EleoNora [17]

If no frictional work is considered, then the energy of the system (the driver at all positions is conserved.

Let
position 1 = initial height of the diver (h₁), together with the initial velocity (v₁).
position 2 = final height of the diver (h₂) and the final velocity (v₂).

The initial PE = mgh₁ and the initial KE = (1/2)mv₁²
where g = acceleration due to gravity,
m = mass of the diver.
Similarly, the final PE and KE are respectively mgh₂ and (1/2)mv₂².
PE in position 1 is converted into KE due to the loss in height from position 1 to position 2.

Therefore
(KE + PE) ₁ = (KE + PE)₂

Evaluate the given answers.
A) The total mechanical energy of the system increases.
FALSE

B) Potential energy can be converted into kinetic energy but not vice versa.
TRUE

C) (KE + PE)beginning = (KE + PE) end.
TRUE

D) All of the above.
FALSE

4 0

3 years ago

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