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3 years ago

Basic design elements include (Check 7)

Physics

1 answer:

myrzilka [38]3 years ago

4 0

Answer: depth, shade, fragrance

Explanation:

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Difference between sold and liquid

Tcecarenko [31]

Explanation:

Solids have closely packed particles and vibrate about a fixed position, they also have a fixed volume.

liquid have close particles but which are able to move with a bit of kinetic energy, for this reason they have no fixed volume but take the volume of the container or vessel

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3 years ago

The work of brain mind interface is to

Genrish500 [490]

The work of Brian mind interface is to learn that’s my guess lol

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4 years ago

What is the MOST LIKELY effect of deforestation that results from urbanization of an area?

KengaRu [80]

A. Erosion is the answer

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4 years ago

Read 2 more answers

PLEASE HELP ME WITH THIS ONE QUESTION

shtirl [24]

Answer:

$\lambda=1.39\times 10^{-4}\ s^{-1}$

Explanation:

Given that,

The half-life of Barium-139 is $4.96\times 10^3$

A sample contains $3.21\times 10^{17}$ nuclei.

We need to find the decay constant for this decay. The formula for half life is given by :

$T_{1/2}=\dfrac{0.693}{\lambda}\\\\\lambda=\dfrac{0.693}{T_{1/2}}$

Put all the values,

$\lambda=\dfrac{0.693}{4.96\times 10^3}\\\\=1.39\times 10^{-4}\ s^{-1}$

So, the decay constant is $1.39\times 10^{-4}\ s^{-1}$ .

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3 years ago

Two forces P and Q act on an object of mass 11.0 kg with Q being the larger of the two forces. When both forces are directed to

alexgriva [62]

Answer:

The magnitude of force on P is 2.75 N

The magnitude of force on Q is 7.15 N

Solution:

As per the question:

Mass of the object, M = 11.0 kg

Acceleration of the object when the forces are directed leftwards, a = $0.900 m/s^{2}$

Acceleration when the forces are in opposite direction, a' = $0.400 m/s^{2}$

Now,

The net force on the object in first case is given by:

$F_{net} = |\vec{F_{P}}| + |\vec{F_{Q}}| = Ma$ (1)

The net force on the object in second case is given by:

$F_{net} = |\vec{F_{P}}| - |\vec{F_{Q}}| = Ma'$ (2)

Adding both eqn (1) and (2):

$2|\vec{F_{Q}}| = M(a + a')$

$|\vec{F_{Q}}| = \frac{11.0(0.900 + 0.400)}{2} = 7.15 N$

Putting the above value in eqn (1):

$|\vec{F_{P}}| = 11\times 0.900 - |\vec{F_{Q}}|$

$|\vec{F_{P}}| = 9.900 - 7.15 = 2.75$

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4 years ago