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pantera1 [17]
3 years ago
5

PLEASE HELP ME WITH THIS ONE QUESTION

Physics
1 answer:
shtirl [24]3 years ago
4 0

Answer:

\lambda=1.39\times 10^{-4}\ s^{-1}

Explanation:

Given that,

The half-life of Barium-139 is 4.96\times 10^3

A sample contains 3.21\times 10^{17} nuclei.

We need to find the decay constant for this decay. The formula for half life is given by :

T_{1/2}=\dfrac{0.693}{\lambda}\\\\\lambda=\dfrac{0.693}{T_{1/2}}

Put all the values,

\lambda=\dfrac{0.693}{4.96\times 10^3}\\\\=1.39\times 10^{-4}\ s^{-1}

So, the decay constant is 1.39\times 10^{-4}\ s^{-1}.

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allsm [11]

Answer:

A) An organism with favorable genetic variation will tend to survive and breed successfully.

Explanation:

In an ecosystem, organisms that don't have the best genetic variation will die off, leaving the more genetic favored ones to survive and become better as a whole.

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The carbon cycle is powered by which two processes?
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Answer:

the answer is the last one

Explanation:

here is the definition:

(i know how to explain the answer, its merely unnecessary being that there is an offical definition.)

<em>the series of processes by which carbon compounds are interconverted in the environment, involving the incorporation of carbon dioxide into living tissue by photosynthesis and its return to the atmosphere through respiration, the decay of dead organisms, and the burning of fossil fuels.</em>

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3 years ago
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Obtain a volume of 12.5 millimeters of liquid in the diagram
tiny-mole [99]

Answer:

D remove 1.5 ML of liquid.

Explanation:

     

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Hola! necesito las respuestas de "fuerzas"
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I need help on this to I have to get the answer fast
5 0
4 years ago
A vehicle of mass 100kg has a kinetic energy of 5000 J at an instant. The velocity at that instant is​
snow_lady [41]

Answer:

  • \bf\pink{10\:m/s}

Explanation:

<h2><u>Given</u> :-</h2>

  • \sf\red{Mass \ of \ vehicle \ (m) = 100 \ kg}
  • \sf\orange{Kinetic \ energy \ (K.E.) = 5000 \ J}

<h2><u>To Find</u> :-</h2>

  • \sf\green{Velocity\: of\: the \:vehicle \:at \:the \:instant}

<h2><u>Formula to be used</u> :-</h2>

  • \sf\blue{K.E. = \dfrac{1}{2} mv^{2}}

Where,

  • K.E. = Kinetic energy possessed by the body
  • M = Mass of the body
  • V = Velocity of the body

<h2><u>Solution</u> :-</h2>

\to\:\:\sf\red{K.E. = \dfrac{1}{2}mv^{2}}

\to\:\:\sf\orange{5000 = \dfrac{1}{2} \times 100 \times v^{2}}

\to\:\:\sf\green{5000 = 50 \times v^{2}}

\to\:\:\sf\blue{\dfrac{5000}{50} = v^{2}}

\to\:\:\sf\purple{100 = v^{2}}

\to\:\:\sf\red{\sqrt{100} = v}

\to\:\:\sf\orange{ 10 = v}

\to\:\:\bf\pink{v = 10\:m/s}

  • Velocity of the vehicle at the instant is \bf\green{10\:m/s}
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