First student has a 1 minute head start at .20 miles per minute.
This is a distance of .2 miles.
The second student has to make up this distance by running at .25 miles per minute. This produces a net gain on the first student by
(.25 -.20) = .05 miles per minute.
So how long does it take to run .20 miles at .05 miles per hour?
.2 miles / .05 miles per minute = 4 minutes.
Answer:
n=7
Step-by-step explanation:
33-19÷2= 7
sorry if my answer is wrong
-12x-0.4>7.3x+16-55
= -12x-7.3x>16-55+0.4
= -19.3x> -38.6
= x< -38.6/-19.3
= x< 2
I’m just here to gain poit bro don’t listen to me but keep asking 12 58 474 answers B
I'm pretty sure it's 7 and 1/7