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defon
3 years ago
14

BRAINLIEST AWARD WILL BE GIVEN! PLEASE HELP WITH MATH IVE BEEN ASKING FOR HOURS! PLEASE ANYONE!!!

Mathematics
1 answer:
harina [27]3 years ago
3 0
1. (x^2+1)*(x^3+2*x)*(x^2-64)
=(x^2+1)*x*(x^2+2)*(x+8)(x-8)
Solving for each factor in turn, for example, 
x^2+1=0 => x^2=-1 => x=+i, x=-i
x=0 => x=0
x^2+2=0 => x^2=2 => x=+sqrt(2)i, -sqrt(2)i
x+8=0 => x=-8
x-8=0 => x=+8
we have solution set
S, whereS={+i, -i, 0, +sqrt(2)i, -sqrt(2)i, -8, +8)

2. A.
x^4-81=0 => x^4=81 => x^2=+9 or x^2=-9
x^2=+9  => x=+3, -3
x^2=-9  => x=+3i, -3i
S={+3i, -3i, +3, -3}

B.
x^4+10x^2+25=0 => (x^2+5)^2=0 => ± (x^2+5)=0 => x^2=-5
=> x=+sqrt(5)i (multiplicity 2 and x=-sqrt(5)i (multiplicity 2)
S={+sqrt(5)i (multiplicity 2) -sqrt(5)i (multiplicity 2)}

C.
x^4-x^2-6=0 => (x^2-3)(x^2+2)=0 => x^2=3 or x^2=-2
S={+sqrt(2)i,-sqrt(2)i, +sqrt(3), -sqrt(3) }

3.
x^4+3x^2-4=0 = (x^2-1)(x^2+4) => x^2=1 or x^2=-4
S={+2i, -2i, +1, -1}
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Solve. Round to the nearest tenth.<br> 6<br> 2-12<br> 19<br> 2x-2<br> HELP ASAP!!
Strike441 [17]

Answer:

\displaystyle x = \frac{216}{7}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \frac{6}{19} = \frac{x - 12}{2x - 2}<u />

<u />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Cross-multiply:                     \displaystyle 6(2x - 2) = 19(x - 12)
  2. Distribute:                             \displaystyle 12x - 12 = 19x - 228
  3. Isolate <em>x</em> terms:                     \displaystyle -12 = 7x - 228
  4. Isolate <em>x</em> term:                      \displaystyle 216 = 7x
  5. Isolate <em>x</em>:                               \displaystyle \frac{216}{7} = x
  6. Rewrite:                                \displaystyle x = \frac{216}{7}
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