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kow [346]
3 years ago
8

Let ŷ represent the profit (in thousands of dollars) for a certain company x years after 1970. A statistician calculates a linea

r model ŷ = 0.66 x + 12 Use the model to estimate the profit in 1978. Your answer should be in dollars, not thousands of dollars.
Mathematics
1 answer:
Anika [276]3 years ago
5 0

Answer:

$17,280

Step-by-step explanation:

The model for profit (y), in thousands of dollars, as a function of time (x), in years after 1970 is:

y=0.66x +12

The corresponding value of x in 1978 is:

x= 1978-1970\\x=8

Estimating the profit (in thousands of dollars) in 1978:

y(8)=0.66*8 +12\\y(8) = 17.28

Converting it to dollars:

P = \$1,000*y(8)= \$1,000*17.28\\P= \$17,280

The estimated profit in 1978 is $17,280.

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Many airline companies have begun implementing fees for checked bags. Economic theory predicts that passengers will respond to t
valentinak56 [21]

Answer:

Step-by-step explanation:

a. The hypothesis test is  one tailed_____ test.

(Because we check whether sample weight is greater than hence one tailed or right tailed)

The test statistic follows a __t___ distribution.(Because only sample std deviation s is known)

The value of the test statistic is___Mean difference/Std error =\frac{17.1-16}{\frac{6}{\sqrt{67} } } \\=1.58__

b. df = 66

Reject H0 if t ≥ 1.668

c. The p-value is_____0.059444

d. Using the critical value approach, the null hypothesis is _accepted____, because __t <1.668___ Using the p-value approach, the null hypothesis is__accepted___, because__p value <0.05 our significance level.___ Therefore, you __may___ conclude that the mean weight of the airline's passengers' carry-on items has increased after the implementation of the checked-bag fee.

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3 years ago
Steph makes 90 % 90%90, percent of the free throws she attempts. She is going to shoot 3 33 free throws. Assume that the results
zmey [24]

Using the binomial distribution, it is found that there is a 0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

For each free throw, there are only two possible outcomes, either he makes it, or he misses it. The results of free throws are independent from each other, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • He makes 90% of the free throws, hence p = 0.9.
  • He is going to shoot 3 free throws, hence n = 3.

The probability that he makes exactly 1 is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.9)^{1}.(0.1)^{2} = 0.027

0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

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