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mrs_skeptik [129]
3 years ago
15

If JK and LM are congruent and parallel, then JKL and MLK are congruent.

Mathematics
1 answer:
viktelen [127]3 years ago
3 0

Answer:

Given statement is TRUE.

Step-by-step explanation:

Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.

We know that corresponding angles formed by transversal line are congruent.

Hence ∠JKL = ∠ MLK ...(i)

Now consider triangles JKL and MLK

JK = LM  {Given}

∠JKL = ∠ MLK { Using (i) }

KL = KL  {common sides}

Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.

Hence given statement is TRUE.

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Five numbers has a mean of 12. When one (1) number is removed the mean is 11. What is the value of the number removed?
bonufazy [111]

Answer:

16

Step-by-step explanation:

The mean of a group of values is calculated as

mean = \frac{sum}{count}

Given 5 numbers with a mean of 12, then

\frac{sum}{5} = 12 ( multiply both sides by 5 )

sum = 60

let the number removed be x , then

\frac{60-x}{4} = 11 ( multiply both sides by 4 )

60 - x = 44 ( subtract 60 from both sides )

- x = - 16 ( multiply both sides by - 1 )

x = 16

The number removed was 16

6 0
3 years ago
apparently this is explains to find the linear function by the table ( given) but in slope intercept form ( please help me :') )
nika2105 [10]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please please help me please help please please help me please help please
AVprozaik [17]

Answer:

Perimeter is 17.07

Step-by-step explanation:

We know that DF = EF = 5 cm, since D and E are the midpoints of AC and AB, both of which are 10 cm in length.

We need to use the Pythagorean theorem to get the length of DE.

DE = \sqrt{5^{2} +5^{2}}=\sqrt{50}  = 7.07\\

So the perimeter of DEF is 5 + 5 + 7.07 = 17.07

5 0
3 years ago
Which statement is true? Select all that apply.
julsineya [31]
It’s b and c and i believe a
3 0
2 years ago
Because of a virus introduced into a bacterial culture, the population of the bacteria decreasedfrom 3000 to 1000 in 50 minutes.
Mamont248 [21]

Answer:

208

Step-by-step explanation:

Given that;

Given that;

y= a(1 - b)^t

Where;

wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.

To obtain the constant b,

y= ae^-bt

Substituting values;

1000 = 3000 e^-b(50)

1000/3000 = e^b(50)

0.33 = e^b-(50)

ln (0.33) = ln(e^b(-50))

-1.1 = -50b

b= 1.1/50

b= 0.022

After two hours or 120 minutes;

y= 3000(1 - 0.022)^120

y= 207.8661772

y= 208

8 0
3 years ago
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