All there is, is a picture. Is there a question?
To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
Answer:
False
<em>Brainliest, please!</em>
Step-by-step explanation:
+ + = +
- - = +
+ - = -
- + = -
The value would be $14,000.
The formula we use for this is
A = p(1+r)ˣ, where p is the initial value, r is the percent of depreciation (as a decimal number) and x is the number of years. Note that since it is depreciation, r will be a negative number.
A = 25000(1-0.08)⁷ = 13946.17 ≈ 14000
Answer:
98
Step-by-step explanation:
4=x56×7
4=x392
392/4=X
98
