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1 year ago

HELPPOO MEEEEE plessss

Mathematics

1 answer:

Viktor [21]1 year ago

6 0

the answer is yes. Why? Because if you move a vertical line across the graph, at any given moment, it only touches one point. If it touched more than one point it wouldn't be a function.

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Find the zeros of the function g(x) = x2 - 6x - 16 by factoring. what is the largest zero of the function? enter a number only.

aleksandrvk [35]

(X-8)(x+2) is the factored equation. Ur zeros r -2 and 8. So the largest should be 8?

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2 years ago

Is the binomial a factor of the polynomial nominal function?

Sedbober [7]

The factors for given equation f(x)= $x^{3} +3x^{2} -25x-75$ .

(x-1) - No
(x-3) - No
(x+3) - Yes
(x-5) - Yes
(x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)= $x^{3} +3x^{2} -25x-75$ .

Add 0 at the end of the equation.

$x^{3} +3x^{2} -25x-75$ = 0.

Let us group the given equation,

$(x^{3} +3x^{2}) -(25x-75)$ =0.

⇒ Group 1: $x^{3} +3x^{2}$ .

Group 2: $- 25x +75$ .

Pull out factor from each group,

⇒ Group 1: $(x+3)(x^{2})$ .

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

$(x+3)(x^{2} -25)$ =0.

One of the factor is (x+3).

Other factors are solved by the formula, $a^{2}-b^{2} = (a+b) (a-b)$ .

$(x+3)(x^{2} -25)$ = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

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An=an-1-3

I hope this helps.

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